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frozen [14]
2 years ago
11

A particle with charge q, mass m, and initial speed v0 in the x direction enters a region where the electric field is uniform in

the x direction. How much time does it take for the particle to cross the region of length d
Physics
1 answer:
Nezavi [6.7K]2 years ago
8 0

Answer:

S = 1/2 Vo t + 1/2 a t^2 = d      time for particle to travel distance d

F = E q         force acting on particle

a = F / m = E q / m

d = Vo t + E q / (2 m) t^2

One would need to solve the quadratic equation shown to find the time t

t^2 + (2 m) / E q * V0 t - (2 m) / E q * d = 0

or t^2 + A V0 t - A d = 0 where A =  (2 m) / E q

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weqwewe [10]

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The friends take a few minutes to discuss their ideas. Which of Amy's comments with respect to a charged particle moving in a ma
Marizza181 [45]

Answer:

The statement "if the magnetic force is always perpendicular to the velocity, the path of the particle is a straight line" is false.

Explanation:

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From it we can clearly see that the <em>magnitude of the magnetic force </em>exerted on the particle is <em>proportional to the magnitude of the charge q and to the speed v of the particle</em>, and that it is also <em>perpendicular to the particle's velocity</em>. This means that at each instant it moves perpendicularly to the force, so <em>the work done by the magnetic force on the particle is zero</em>.

The statement "if the magnetic force is always perpendicular to the velocity, the path of the particle is a straight line" is false not only for this but for any force, a force always perpendicular to a velocity will curve the trajectory.

7 0
2 years ago
1. How far away must you be from a 675 kHz radio station with power 50.0 kW for there to be only one photon per second per squar
goldenfox [79]

a) 0.321 ly

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A bat hits a 0.150 kg baseball for
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Answer:

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Explanation:

impulse = mass ( change in velocity )

              = mass ( final velocity - initial velocity )

               = 0.150 ( 32.0 - (-47.0))

                = 0.150 ( 32.0 +47.0)

                = 0.150 (79)

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3 0
3 years ago
A 75.0-kg man standing on a bathroom scale in an elevator. Calculate the scale in N, reading if the elevator moves upward at a c
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The scale in N, reading if the elevator moves upward at a constant speed of 1.5 m/s^2 is 862.5 N.

weight of man = 75kg

speed of elevator, a = 1.5 m/ s^{2}

F - w = ma \\

F = w + ma

F = m ( a +g )

F = 75 ( 1.5 + 10 ) \\

F = 75 ( 11.5 )

F = 862.5 N

So, the scale reading in the elevator is greater than his 862.5 N weight. This indicates that the person is being propelled upward by the scale, which it must do in order to do so, with a force larger than his weight. According to what you experience in quickly accelerating or slowly moving elevators, it is obvious that the faster the elevator acceleration, the greater the scale reading.

Speed can be defines as the pace at which the position of an object changes in any direction.  Since speed simply has a direction and no magnitude, it is a scalar quantity.

Learn more about speed here:-

brainly.com/question/19127881

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