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3 years ago

True or false, question in picture,

Physics

2 answers:

lakkis [162]3 years ago

8 0

Answer:

its false

Explanation:

Arlecino [84]3 years ago

3 0

Answer:

false

Explanation:

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Dr. gavin decides that instead of conducting a 2 ´ 4 independent-groups factorial design, he is going to conduct a 2 ´ 4 within-

vampirchik [111]

<span>If Dr. Gavin decides that instead of conducting a 2 ´ 4 independent-groups factorial design, and he is going to conduct a 2 ´ 4 within-subjects factorial design, then the things that will change are the various independent groups which are involved.</span>

8 0

3 years ago

I need help with this question ASAP please :)

Nana76 [90]

Answer: 1.67 x 10-7 N

3 0

3 years ago

An aircraft component is fabricated from an aluminum alloy that has a plane strain fracture toughness of 40 mpa m (36.4 ksi in.

GarryVolchara [31]

We will first determine using the given if an aircraft component will fracture with a given stress level (260 MPa), maximum internal crack length (6.0 mm) and fracture toughness (40 MPa m ), given that fracture occurs for the same component using the same alloy for another stress level and internal crack length. First, it is necessary to solve for the parameter Y, using Equation 8.5, for the conditions under which fracture occurred (i.e., σ = 300 MPa and 2 a = 4.0 mm). Therefore,

Y = K(Ic)/ sqrt(π a) = 40 MPa( m ) / (300 MPa) sqrt(( π ) ((4 × 10-3 m)/2)) = 1.68

We will now solve for the product Y σ π a for the other set of conditions, so as to ascertain whether or not this value is greater than the K(Ic) for the alloy. Thus,

Y sqrt(π a) = (1.68)(260 MPa) sqrt (( π )[(6 × 10^-3 m)/ 2])
= 42.4 MPa sqrt (m) (39 ksi in. )

Therefore, fracture will occur since this value ( 42.4 MPa sqrt(m)) is greater than the K(Ic) of the material, 40 MPa sqrt(m).

8 0

4 years ago

A cricket ball has mass 0.155 kg. If the velocity of a bowled ball has a magnitude of 35.0 m/s and the batted ball's velocity is

FinnZ [79.3K]

Answer:

Magnitude of change in momentum = 4.65 kg.m/s

Magnitude of impulse = 4.65 kg.m/s

Magnitude of the average force applied by the bat = 1550 N

Explanation:

Mass of the cricket ball, m = 0.155 kg

Initial velocity of the ball, u = 35.0 m/s

final velocity of the ball after hitting the bat, v = 65.0 m/s

Time of contact, t = 2.00 ms = 2.00 × 10⁻³ s

Now,

Magnitude of change in momentum = Final momentum - Initial momentum

Magnitude of change in momentum = ( m × v ) - ( m × u )

Magnitude of change in momentum = ( 0.155 × 65 ) - ( 0.155 × 35 )

Magnitude of change in momentum = 10.075 - 5.425 = 4.65 kg.m/s

Now, Magnitude of impulse = change in momentum

thus,

Magnitude of impulse = 4.65 kg.m/s

Now,

magnitude of the average force applied by the bat = $\frac{\textup{Impulse}}{\textup{Time}}$

magnitude of the average force applied by the bat = $\frac{\textup{4.65}}{\textup{3}\times\textup{10}^{-3}}$

Magnitude of the average force applied by the bat = 1550 N

6 0

4 years ago

A charged particle enters into a uniform magnetic field such that its velocity vector is perpendicular to the magnetic field vec

Ugo [173]

Answer:

a circular path

Explanation:

In a magnetism field if a charged particle having a charge of magnitude '' enters such that its velocity vector V is 90° to the direction of the magnetic field "B'', then it will experience a force, called Lorentz force F

$F = V\times B$

According to the property of cross-product, the Lorentz force (F) acting on the particle will be perpendicular to the instantaneous position of the particle, making the path of the particle to be a circular path.

3 0

3 years ago