Answer:
The answer is "
"
Explanation:
Please find the complete question in the attached file.
Using formula:
Given:
put the value into the above-given formula:
I'm sorry but I don't see anything that says part B
.
<span>The concept of plate tectonics regards the earth's CRUST as broken into a number of TECTONIC PLATES that are in motion relative to each other</span>
Answer:
Explanation:
The question relates to motion on a circular path .
Let the radius of the circular path be R .
The centripetal force for circular motion is provided by frictional force
frictional force is equal to μmg , where μ is coefficient of friction and mg is weight
Equating cenrtipetal force and frictionl force in the case of car A
mv² / R = μmg
R = v² /μg
= 26.8 x 26.8 / .335 x 9.8
= 218.77 m
In case of moton of car B
mv² / R = μmg
v² = μRg
= .683 x 218.77x 9.8
= 1464.35
v = 38.26 m /s .
