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irinina [24]
3 years ago
8

Mr. Fuller assigned his science class a lab comparing the masses of objects to the nearest gram using a balance. The mass of a p

aper clip is about 1 gram. How many paper clips will it take to balance the scale, if it is determined that a 1 centimeter cube of aluminum has the mass of 2.7 grams?
Physics
1 answer:
Tomtit [17]3 years ago
5 0
The scale would need 10 aluminum cubes on one side. Figure out how many paper clips would be needed on the other side to balance this. You have to use more than one aluminum cube because you need to have enough cubes so that you get a whole number mass. 10 cubes gives you a total mass of 27 g for the aluminum.
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How does mass effect acceleration
kompoz [17]

Answer:

the bigger the mass the lesser the acceleration and vice versa

Explanation:

this is because the acceleration is a function of the mass and this can be proven by the formula for force: F = ma

7 0
2 years ago
If a ball is dropped from a height of 10 m, hits the ground and bounces back up to a maximum height of 7.5 m, describe how the E
Greeley [361]

Answer:hmmmm

Explanation:

8 0
3 years ago
32. (FR) A mass moving at 25 m/s slides along a rough horizontal surface. The coefficient of friction is 0.30. (A) Use force and
scoray [572]

Answer:

A)s = 104.16 m

b)s= 104.16 m

Explanation:

Given that

u = 25 m/s

μ = 0.3

The friction force will act opposite to the direction of motion.

Fr= μ m g

Fr= -  m a

a=acceleration

μ m g = - m a

a= - μ g

a= - 0.3 x 10 m/s²          ( take g= 10 m/s²)

a= - 3  m/s²

The final speed of the mass is zero ,v= 0

We know that

v² = u² +2 a s

s=distance

0² = 25² - 2 x 3 x s

625 = 6 s

s = 104.16 m

By using energy conservation

Work done by all the forces =Change in the kinetic energy

- Fr.s=\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2

Negative sign because force act opposite to the displacement.

- \mu\ m\ g \ s=\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2

-\mu\ g \ s=\dfrac{1}{2}v^2-\dfrac{1}{2}u^2

-0.3\times 10\times \ s=\dfrac{1}{2}\times 0^2-\dfrac{1}{2}\times 25^2

- 3 x 2 x s = - 625

s= 104.16 m

4 0
3 years ago
A string is wrapped around a pulley with a radius of 2.0 cm. The pulley is initially at rest. A constant force of 50 N is applie
Ray Of Light [21]

Answer:

0.20kg-m^2

Explanation:

Let the linear velocity of the rope(=of pulley) is v m/s

Using kinematic equation

=> v = u + at

=>v = 0 + 4.9a

=>v = 4.9a ------------ eq1

By v^2 = u^2 + 2as

=>v^2 = 0 + 2 x v/4.9 x 1.2

=>4.9v^2 - 2.4v = 0

=>v(4.9v - 2.4) = 0

=>v = 2.4/4.9 = 0.49 m/s

Thus by v = r x omega

=>omega = v/r = 0.49/0.02 = 24.49 rad/sec

BY W = F x s = 50 x 1.2 = 60 J

=>KE(rotational) = W = 1/2 x I x omega^2

=>60 = 1/2 x I x (24.49)^2

=>I = 0.20 kg-m^2

5 0
3 years ago
Calculate the current through a 3.0 ω resistor with a voltage of 9.0 v across it.
gulaghasi [49]

Answer: 3 A

Explanation:

According to<u> Ohm's law</u>:  

V=R.I

Where:

V=9 V is the voltage

R=3\Omega is the resistance of the resistor

I is the electric current (the value we want to find)

Isolating I:

I=\frac{V}{R}

I=\frac{9 V}{3\Omega}

Finally:

I=3 A

7 0
3 years ago
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