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3 years ago

What is an Amplitude

2 answers:

5 0

DescriptionThe amplitude of a periodic variable is a measure of its change in a single period. There are various definitions of amplitude, which are all functions of the magnitude of the differences between the variable's extreme values. In older texts the phase is sometimes called the amplitude.

dangina [55]3 years ago

3 0

Amplitude is a measurement of the magnitude of displacement (or maximum disturbance) of a medium from its resting state, as diagramed in the peak deviation example below (it can also be a measurement of an electrical signal's increased or decreased strength above or below a nominal state).

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Explain how you can use Boyle's law to determine the new volume of gas when its pressure is increased from 270kPa to 540kPa? The

ivann1987 [24]

I hope this is what you are looking for P1 = 270 kPa V1 = 1 L P2 = 540 kPa V2 = ? Use Boyle's Law: P1V1 = P2V2 V2 = P1 V1 / P2 V2 = 270 x 1 / 540 V2 = 0.5 L

4 0

2 years ago

2 (a) What is the distance from the Sun to Earth in terms of solar radii? Earth radii?

ohaa [14]

a) Distance Earth-Sun is 215.5 solar radii and 23,548 Earth radii

Mercury: 1.7 days

Mars: 6.5 days

Jupiter: 21.7 days

Uranus: 86.8 days

Neptune: 130.2 days

c) $1.3\cdot 10^6$ Earths can fit inside the Sun

Explanation:

The distance between the Sun and the Earth is 150 millions km, so

$d=150\cdot 10^6 km = 1.50\cdot 10^{11} m$

The solar radius is

$r_s = 6.96\cdot 10^5 km = 6.96\cdot 10^8 m$

Therefore the distance Earth-Sun in solar radii is

$d_s = \frac{d}{r_s}=\frac{1.50\cdot 10^{11}}{6.96\cdot 10^8}=215.5$

The Earth radius is

$r_e = 6.37\cdot 10^6 m$

Therefore the distance Earth-Sun in Earth radii is

$d_e=\frac{d}{r_e}=\frac{1.50\cdot 10^{11}}{6.37\cdot 10^6}=23,548$

The speed of the solar wind is

$v=400 km/s = 4\cdot 10^5 m/s$

The value of 1 AU (Astronomical Unit) is

$1 AU = 1.50\cdot 10^{11}m$ (distance Earth-Sun)

The distance between the Sun and Mercury is:

$d=0.4 AU \cdot 1.50\cdot 10^{11}=6.0\cdot 10^{10} m$

So the time taken by a parcel of solar wind to reach Mercury is:

$t=\frac{d}{v}=\frac{6.0\cdot 10^{10}}{4.0\cdot 10^5}=150,000 s$

Converting into days ( $1d=86400 s$ ),

$t=\frac{150,000}{86400}=1.7 d$

The distance between the Sun and Mars is:

$d=1.5 AU \cdot 1.50\cdot 10^{11}=2.25\cdot 10^{11} m$

So the time taken by a parcel of solar wind to reach Mars is:

$t=\frac{d}{v}=\frac{2.25\cdot 10^{11}}{4.0\cdot 10^5}=562,500 s$

Converting into days ( $1d=86400 s$ ),

$t=\frac{562,500}{86400}=6.5 d$

The distance between the Sun and Jupiter is:

$d=5 AU \cdot 1.50\cdot 10^{11}=7.5\cdot 10^{11} m$

So the time taken by a parcel of solar wind to reach Jupiter is:

$t=\frac{d}{v}=\frac{7.5\cdot 10^{11}}{4.0\cdot 10^5}=1.88 \cdot 10^6 s$

Converting into days ( $1d=86400 s$ ),

$t=\frac{1.88\cdot 10^6}{86400}=21.7 d$

The distance between the Sun and Uranus is:

$d=20 AU \cdot 1.50\cdot 10^{11}=3.0\cdot 10^{12} m$

So the time taken by a parcel of solar wind to reach Uranus is:

$t=\frac{d}{v}=\frac{3.0\cdot 10^{12}}{4.0\cdot 10^5}=7.5 \cdot 10^6 s$

Converting into days ( $1d=86400 s$ ),

$t=\frac{7.5\cdot 10^6}{86400}=86.8 d$

The distance between the Sun and Neptune is:

$d=30 AU \cdot 1.50\cdot 10^{11}=4.5\cdot 10^{12} m$

So the time taken by a parcel of solar wind to reach Neptune is:

$t=\frac{d}{v}=\frac{4.5\cdot 10^{12}}{4.0\cdot 10^5}=11.3 \cdot 10^6 s$

Converting into days ( $1d=86400 s$ ),

$t=\frac{11.3\cdot 10^6}{86400}=130.2 d$

As we said in part a), we have:

$r_e = 6.37\cdot 10^6 m$ (radius of the Earth)

$r_s=6.96\cdot 10^8 m$ (radius of the Sun)

So the volume of the Earth can be calculated as:

$V_e=\frac{4}{3}\pi r_e^3 = \frac{4}{3}\pi (6.37\cdot 10^6)^3=1.08\cdot 10^{21} m^3$

While the volume of the Sun is

$V_s=\frac{4}{3}\pi r_s^3 = \frac{4}{3}\pi (6.96\cdot 10^8)^3=1.41\cdot 10^{27} m^3$

Therefore, the number of Earths that could fit inside the Sun is:

$\frac{V_s}{V_e}=\frac{1.41\cdot 10^{27}}{1.08\cdot 10^{21}}=1.3\cdot 10^6$

Learn more about the Solar System:

brainly.com/question/2887352

brainly.com/question/10934170

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6 0

3 years ago

A diagram of the carbon-oxygen cycle is shown below.

goldfiish [28.3K]

B.plants is responsible of removing carbon dioxide

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3 years ago

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HELPPPPPPPPPPPPPPPPPPPPPPPPPP

aev [14]

Answer:

Explanation:

through the desk....here desk is the student's medium to hear the sound. its oblivious because when he lifts his head away from the desk he hears nothing else

6 0

2 years ago

What is the force that can cause two pieces of iron to attract each other?

Rudiy27

Answer:

B. Magnetic Force

Explanation:

two pieces of irons cannot attract each other unless at least one of them is magnetize. That force is called magnetism.

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3 years ago

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