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NARA [144]
2 years ago
10

What letter is located at approximately

Mathematics
1 answer:
Svetradugi [14.3K]2 years ago
6 0

Answer: B

Step-by-step explanation:

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Write a TRUE statement using the words acute angle and regular octagan.<br><br> THANK YOU!!
marishachu [46]
In a regular octagon it is impossible to have an acute angle!
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3 0
3 years ago
Read 2 more answers
Angle Addition Crossword
Elena-2011 [213]

Answer:

Step-by-step explanation:

1). m∠AEC = m∠AEB + m∠BEC

                  = 21° + 37°

                  = 58°

2). m∠BED = m∠BEC + m∠CED

                   = 37° + 44°

                   = 81°

3). m∠IKF = m∠IKH + m∠HKG + m∠GKF

                = m∠IKH + m∠HKG + m∠IKH [Since, ∠IKH ≅ ∠GKF]

                = 2∠IKH + m∠HKG

         103° = 2∠IKH + 41°

   2(∠IKH) = 103 - 41

 m(∠IKH) = 31°

4). m∠AED = m∠AEB + m∠BEC + m∠CED

                  = 21° + 37° + 44°

                  = 102°

5). m∠JKG = 108°

    m∠JKG = m∠JKI + m∠IKH + m∠HKG

    108° = m∠JKI + 31° + 41°

    m∠JKI = 108° - 72°

    m∠JKI = 36°

6). m∠HKF = m∠GKF + m∠HKG

                  = m∠IKH + m∠HKG [Since, m∠GKF = m∠IKH]

                  = 31° + 41°

                  = 72°

7). m∠NQO = m∠MQN = 64°

8). m∠JKF = m∠JKI + m∠IKF

                 = 36° + 103°

                  = 139°

8). m∠MQO = 2(m∠NQO)

                    = 2(64)°

                    = 128°

9). m∠LQO = 156°

    m∠LQM = m∠LQO - m∠MQO

                    = 156° - 128°

                    = 28°

10. m∠NQP = m∠NQO + m∠OQP

                   = 64° + m∠LQM [Since ∠OQP ≅ ∠LQM]

                   = 64° + 28°

                   = 92°

5 0
3 years ago
Hey can I have some quick help please?<br> Is the answer I chose correct?
Gennadij [26K]

Answer:

Yes, I am 99% sure your right.

8 0
3 years ago
Type the correct answer in the box. Use numerals instead of words. Tony bought a new car at a cost of $20,000. The value of the
Over [174]

9514 1404 393

Answer:

  A(x) = 20000(0.88)^x

Step-by-step explanation:

The general form of these exponential equations is ...

  A(x) = a·b^x

where 'a' is the initial value, and b is the annual growth factor. x is the elapsed time in years.

The growth factor is ...

  growth factor = 1 + growth rate

Here, the growth rate per year is -12%, so the growth factor is ...

  b = 1 -12% = 88% = 0.88

Of course, the initial value is a=20,000, so the equation is ...

  A(x) = 20000(0.88)^x

8 0
3 years ago
I need help with 12-14. One answer will get thanks. The highest amount of answers will get brainliest.
boyakko [2]
12. Make equation and plug in

13. Proportion

14. Finding a constant rate, and then manipulate




12. Where x is miles driven, and y is answer, and z is days
      19.95z+0.15x=y
      Plug in two values
      19.95 x 2 + 0.15 x 250 = y
      39.93+37.5 = y
      y=77.43

13. 5:2 as 175:x 
      5/2 = 175/x
      x = 70
      70+175=245

14. 260:5 = x:1
      260/5=x/1
      x = 52
      
      52:1 = y:9
      52/1 = y/9
      y = 468

I hope you understand the process.


7 0
3 years ago
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