Answer:
The 99% confidence interval for p in this case is (0.3317, 0.5883).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
Randomly selects 100 students from the school and asks the President to name each one. The President is able to correctly name 46 of the students.
This means that:
99% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 99% confidence interval for p in this case is (0.3317, 0.5883).
4 also 2 :))))))))))))))))
Answer:
$2.25
Step-by-step explanation:
10*0.10= $1.00
5*0.25= $1.25
1+1.25= $2.25
<span>(4.214) x (3.06) = 12.89484 and can be rounded up to 12.9</span>
Answer:
<em>The answer for the first question is: </em>
<em>12/80 =</em>
<em>12 ÷ 80 =</em>
<em>0.15 =</em>
<em>0.15 × 100/100 =</em>
<em>0.15 × 100% =</em>
<em>(0.15 × 100)% =</em>
<h2><em>
15%</em></h2>
<em>Then, the answer for the second question is: </em>
<em>75% × 52 =</em>
<em>(75 ÷ 100) × 52 =</em>
<em>(75 × 52) ÷ 100 =</em>
<em>3,900 ÷ 100 =</em>
<h2><em>
39 </em></h2>
* Hopefully this helps:) Mark me the brainliest:)!!!
