Hello there! The area of the triangle portion is 11 square units, the area of the rectangle portion is 77 square units, and the area of the entire figure is 88 square units.
To find the area of the triangle, we can follow the formula:
A = LW/2 (which means length x width divided by 2)
Given the formula:
2 • 11 = 22
22 divided by 2 gives us 11 square units.
To find the area of the rectangle portion, we can follow the area formula:
A = LW (which means area = length x width)
Given the formula:
7 • 11 = 77 square units
To find the area of the whole figure, we add the areas of both isolated shapes:
11 + 77 = 88 square units.
Therefore, our area for the entire figure is 88 square units. If you need any extra help, let me know and I will gladly assist you.
Answer:500
Step-by-step explanation:
Step by step
1.50x = y that should be a good equation hopefully. If it’s wrong I’m so sorry. Also if I were to find the answer I need more of the context of the question
Answer:
0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
![\mu = 83, \sigma = 3](https://tex.z-dn.net/?f=%5Cmu%20%3D%2083%2C%20%5Csigma%20%3D%203)
Find the probability that the diameter of a selected bearing is greater than 85 millimeters.
This is 1 subtracted by the pvalue of Z when X = 85. Then
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{85 - 83}{3}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B85%20-%2083%7D%7B3%7D)
![Z = 0.67](https://tex.z-dn.net/?f=Z%20%3D%200.67)
has a pvalue of 0.7486.
1 - 0.7486 = 0.2514
0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.
When solving this equation you get x = -3.
To solve this, simply follow the order of operations for solving.
----> start by dividing both sides by 5
-----> Now you can transform the front side of the equation to use negative exponents.
![7^{-3} = 7^{x}](https://tex.z-dn.net/?f=%207%5E%7B-3%7D%20%3D%207%5E%7Bx%7D%20%20)
Since both x and -3 are the powers of x, we can eliminate the 7 and just make the exponents equal.
-3 = x