Answer: Answer with Step-by-step explanation:
Since we have given that
Cost of party per person = $20.
Let the number of friends be 'f'.
Let the cost of party be 'p'.
According to question, our equation becomes
p= 2f
So, if p = 100, then f = p/2 = 100/2 = 50 if f = 10, then, p = 2f = 2 • 10 = 20 If p = 300 then, f = 300/2 = 150, If f = 20, then, p = 2f = 2 • 20 = 40 So, Table as follows:
Number of friends cost of party
50 100
10 20
150 300
20 40
5 + 5 + 4 + 2 = 16
16 - 4 = 12
12/16 = 3/4
The probability that the toy will not be green is 3/4.
![\bf (\stackrel{x_1}{10}~,~\stackrel{y_1}{14})\qquad (\stackrel{x_2}{14}~,~\stackrel{y_2}{12}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{12-14}{14-10}\implies \cfrac{-2}{4}\implies -\cfrac{1}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-14=-\cfrac{1}{2}(x-10) \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Bx_1%7D%7B10%7D~%2C~%5Cstackrel%7By_1%7D%7B14%7D%29%5Cqquad%0A%28%5Cstackrel%7Bx_2%7D%7B14%7D~%2C~%5Cstackrel%7By_2%7D%7B12%7D%29%0A%5C%5C%5C%5C%5C%5C%0Aslope%20%3D%20m%5Cimplies%0A%5Ccfrac%7B%5Cstackrel%7Brise%7D%7B%20y_2-%20y_1%7D%7D%7B%5Cstackrel%7Brun%7D%7B%20x_2-%20x_1%7D%7D%5Cimplies%20%5Ccfrac%7B12-14%7D%7B14-10%7D%5Cimplies%20%5Ccfrac%7B-2%7D%7B4%7D%5Cimplies%20-%5Ccfrac%7B1%7D%7B2%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%0A%5Ccline%7B1-1%7D%0A%5Ctextit%7Bpoint-slope%20form%7D%5C%5C%0A%5Ccline%7B1-1%7D%0A%5C%5C%0Ay-y_1%3Dm%28x-x_1%29%0A%5C%5C%5C%5C%0A%5Ccline%7B1-1%7D%0A%5Cend%7Barray%7D%5Cimplies%20y-14%3D-%5Ccfrac%7B1%7D%7B2%7D%28x-10%29%0A%5C%5C%5C%5C%5B-0.35em%5D%0A~%5Cdotfill)
now, the x-axis has years after 1987, so 2007 is 20 years after 1987, 1987 + 20 = 2007, therefore x = 20, what is y?............
.
and you know how much that is.
Answer:
6
Step-by-step explanation:
-A sample space is statistically defined as the possible number of outcomes.
-A cube has a total of six sides.
-The result of each toss can result in any one of the 6 faces with equal probability.
-The sample space is therefore 6
Step 3 is incorrect , bradan should have cube rooted both sides instead of dividing it by 3
