3 years ago

A compressed spring does not have elastic potential energy.

Physics

1 answer:

Alexus [3.1K]3 years ago

6 0

Answer:

False

Explanation:

The second you let go its gonna release kinetic energy that's why it's potential

You might be interested in

Question 6(Multiple Choice Worth 2 points)

nikklg [1K]

I believe the answer is the first one.

8 0

3 years ago

Please help with this conversion question about heat!<br> WILL MARK BRAINLIEST!!!

Alexxx [7]

The first answer.

100 Celsius = 373.15 Kelvin

100 Celsius = 212 Fahrenheit

So:

373 Kelvin, 100 degrees Celsius, 212 degrees Fahrenheit.

5 0

3 years ago

Read 2 more answers

If you throw two bowling balls up, each with different mass, does the lightest one go the highest? Why(include the factor of dra

Ber [7]

Yes the lightest one will go the highest. if 2 objects with the same mass like a kilogram of feathers and a kilogram of steel they both would hit the ground at the same time bec they are both a kilogram

8 0

3 years ago

Write down the principals of them lever in points .

Juli2301 [7.4K]

The major principal of leaver is

load × load distance = effort × effort distance

where,

effort dis= distance between effort and fulcrum

load distance = distance between load and fulcrum......

6 0

3 years ago

A woman with mass 50 kg is standing on the rim of a large disk that is rotating at 0.80 rev/s about an axis through its center.

My name is Ann [436]

Answer:

angular momentum, $L=1.4\times 10^4\ kg-m^2/s$

Explanation:

Given that,

Mass of the woman, m = 50 kg

Angular velocity of the disk, $\omega=0.8\ rev/s=5.02\ rad/s$

Mass of the disk, m' = 2670 kg

Radius of the disk, R = 4 m

We need to find the magnitude of the total angular momentum of the woman–disk system. The moment of inertia of the system is equal to the sum of moment of inertia of women and the moment off inertia of the disk.

$I=mR^2+\dfrac{1}{2}m'R^2\\\\I=R^2(m+\dfrac{1}{2}m')\\\\I=(4)^2\times (50+\dfrac{1}{2}\times 270)\\\\I=2960\ kg-m^2$

The angular momentum is given by :

$L=I\omega\\\\L=2960\times 5.02\\\\L=14859.2\ kg-m^2/s$

$L=1.4\times 10^4\ kg-m^2/s$

So, the magnitude of the total angular momentum of the woman–disk system is $1.4\times 10^4\ kg-m^2/s$ . Hence, this is the required solution.

7 0

3 years ago