<span>idk why they want the dratted "k" . it is so simple w/o it !
in the form y = ab^x, a = 4000, b = 4400/4000 = 1.1, x = t/2
N = 4000*1.1^(13/2) = 7432 <------
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now you won't be satisfied with simplicity, so
4400 = 4000e^2k
e^2k = 1.1
k = ln 1.1/2 = .0477 to 4 dp
N(13) = 4000e^(13*.0477) = 7436 <------
note that apart from a roundabout way, you get a less accurate ans !</span>
Answer:
13.2 miles
Step-by-step explanation:
To solve this, we will need to first solve for the base of the triangle and then use the information we find to solve for the shortest route.
(5.5 + 3.5)² + b² = 15²
9² + b² = 15²
81 + b² = 225
b² = 144
b = 12
Now that we know that the base is 12 miles, we can use that and the 5.5 miles in between Adamsburg and Chenoa to find the shortest route (hypotenuse).
5.5² + 12² = c²
30.25 + 144 = c²
174.25 = c²
13.2 ≈ c
Therefore, the shortest route from Chenoa to Robertsville is about 13.2 miles.
Answer:
I bc it has an invisible 1 at the side
Answer:
2, 1
Step-by-step explanation:
In the sequence, each number is half of the previous number.
So we would multiply by 1/2 or divide by 2 to find the next number.
We can test this with a few numbers:
64*1/2=32
16*1/2=8
So the first missing number is 1/2 of 4.
1/2*4=2
The second missing number is 1/2 of the first missing number.
1/2*2=1
If you count the squares or units I got 12.
