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omeli [17]
3 years ago
9

A 4-kg box is pushed against a flat 1 point

Physics
1 answer:
Sonja [21]3 years ago
6 0

Answer:

wd = F * D

wd = 100 * 5

wd = 500

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What is the momentum of a baseball with a mass of 4 kg being thrown at a velocity of 84 m/s towards the hitter
Delvig [45]

Answer:

<h3>The answer is 336 kgm/s</h3>

Explanation:

The momentum of an object can be found by using the formula

<h3>momentum = mass × velocity</h3>

From the question

mass = 4 kg

velocity = 84 m/s

We have

momentum = 4 × 84

We have the final answer as

<h3>336 kgm/s</h3>

Hope this helps you

7 0
3 years ago
Read 2 more answers
In one of the classic nuclear physics experiments at the beginning of the 20th century, an alpha particle was accelerated toward
BaLLatris [955]

Answer:

= 4.3 × 10 ⁻¹⁴ m

Explanation:

The alpha particle will be deflected when its kinetic energy is equal to the potential energy

Charge of the alpha particle q₁= 2 × 1.6 × 10⁻¹⁹ C = 3.2 × 10⁻¹⁹ C

Charge of the gold nucleus q₂= 79 × 1.6 × 10⁻¹⁹ = 1.264 × 10⁻¹⁷C

Kinetic energy of  the alpha particle = 5.28 × 10⁶ × 1.602 × 10⁻¹⁹ J ( 1 eV)

=  8.459 × 10⁻¹³

k electrostatic force constant = 9 × 10⁹ N.m²/c²

Kinetic energy = potential energy =   k q₁q₂ / r where r is the closest distance the alpha particle got to the gold nucleus

r = (  9 × 10⁹ N.m²/c² × 3.2 × 10⁻¹⁹ C × 1.264 × 10⁻¹⁷C) / 8.459 × 10⁻¹³

= 4.3 × 10 ⁻¹⁴ m

3 0
4 years ago
What is the demand for resources, such as food, water, and shelter.
andrey2020 [161]
The demand for these things is very high. Everyone wants to have shelter, water, and food. However the demand for shelter is higher because water and food are more accessible.
3 0
3 years ago
All of the following are sources of calories except HELP ASAP!!!
sweet-ann [11.9K]

Answer:

vitamins don't contain calories

8 0
3 years ago
The 10-kg block is held at rest on the smooth inclined plane by the stop block at A. If the 10-g bullet is traveling at 300 m/s
Nadusha1986 [10]

Answer:

d=6.874mm

Explanation:

Linear momentum of the block is conserved in the x\prime direction since the impulsive force due to impact cancels each other internally.

m_bv_b_x=(m_b+m_B)v_x\\(0.01)(300cos 30\textdegree)=(10+0.01)v\\\therefore v=0.259548m/s

Using the conservation of energy to the block system considering the initial position:

T_1+V_1=T_2+V_2\\\\0+0.5(m_b+m_B)v^2=0+(m_b+m_B)gh\\0.5(10+0.01)(0.259548)^2=(0.01+10)(9.8)\\h=0.003437m\\\therefore h=3.437mm

Applying Sine rule:

d=\frac{h}{Sin 30\textdegree}\\d=6.874mm

Hence, the distance the block will slide up is 6.874mm

5 0
3 years ago
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