Answer:
1. Ice at 0 degrees C.
2. N₂ at STP.
3. N₂ at STP.
4. Water vapor at 150 degrees C and 1 atm.
Explanation:
First, we need to remember that entropy (S) is a <em>measure of how spread out or dispersed the energy of a system is among the different possible ways that system can contain energy</em>. The greater the dispersal, the greater is the entropy.
When the temperature is increased, the energies associated with all types of molecular motion increase. Consequently, the entropy of a system always increases with increasing temperature.
With this in mind, we consider the pairs:
1. Since the ice at 0ºC has a greater temperature than the ice at -40 ºC, the first has the higher entropy.
2. The N₂ at STP (that is, 1 atm and 25 ºC) has higher entropy than N₂ at 0ºC and 10 atm because it has a higher temperature and less pressure, which allows a greater dispersal of energy by the molecules of the gas.
3. The N₂ at STP has a higher entropy since it has a higher temperature than N₂ at 0ºC, even though it the first has a lower volume (24,4 L vs. 50 L).
4. The water vapor at 150 ºC and 1 atm have a higher temperature and a lower pressure. This means that its molecules will have an increased molecular motion than the molecules of water vapor at a lower temperature and higher pressure. Therefore, the first has the highest entropy.
Answer:
2.60 moles of A remaining.
Explanation:
According to Le Chatelier's principle, the equilibrium would shift if the volume, concentration, pressure, or temperature changes.
In this question, we were told that the volume doubles, that implies that we would have to double the molarity of B/ C (since B=C.)
However, it is obvious and clear from the given equation of the reaction that A is solid in it's activity = 1. Hence, it is then ignored.
So doubling B would be 1.30 M × 2 = 2.60 M
i.e 2.60 M moles of A was consumed.
Now; the number of moles of A remaining is 5.20 - 2.60 = 2.60 moles of A remaining.
Volume in liters of Carbon dioxide : 0.672
<h3>Further explanation</h3>
Reaction(combustion of butane-C₄H₁₀)
2C₄H₁₀+13O₂⇒8CO₂+10H₂O
mol butane (MW=58,12 g/mol) :
mol CO₂ : mol C₄H₁₀ = 8 : 4, so mol CO₂ :
At STP, 1 mol = 22.4 L, so volume CO₂ :
Out of the following given choices;
A) when there are too many neutrons
B) when the neutrons are slowed down
C) when there is a chain reaction
D) when there is critical mass
The answer is A. A fission nuclear reactor is controlled by regulating the number of neurotoxins produced in the chain reaction. Too many neutrons cause an accelerated chain reaction that causes enormous heat to be generated in a short amount of time which could cause an explosion. Control rods , made of “neutron poisons”, e.g. cadmium, are put in the reactors to control the number of neutrons at any one time
