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Ugo [173]
2 years ago
14

If hydrochloric acid has a [H+] of 1.2 x 10-2 M, what is the pH? 1.9 0 1 1.2 O 8

Chemistry
2 answers:
Vanyuwa [196]2 years ago
7 0

Answer:

<h2>1.9</h2>

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ {H}^{+} ]

From the question we have

pH =  -  log(1.2 \times  {10}^{ - 2} )  \\  = 1.920818...

We have the final answer as

<h3>1.9</h3>

Hope this helps you

marin [14]2 years ago
5 0

Answer:

1.9

Explanation:

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<u>Answer:</u> The heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H

The equation used to calculate enthalpy change is of a reaction is:

\Delta H_{rxn}=\sum [n\times \Delta H_{(product)}]-\sum [n\times \Delta H_{(reactant)}]

For the given chemical reaction:

C_4H_6(g)+2H_2(g)\rightarrow C_4H_{10}(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(1\times \Delta H_{(C_4H_{10})})]-[(1\times \Delta H_{(C_4H_6)})+(2\times \Delta H_{(H_2)})]

We are given:

\Delta H_{(C_4H_{10})}=-2877.6kJ/mol\\\Delta H_{(C_4H_6)}=-2540.2kJ/mol\\\Delta H_{(H_2)}=-285.8kJ/mol

Putting values in above equation, we get:

\Delta H_{rxn}=[(1\times (-2877.6))]-[(1\times (-2540.2))+(2\times (-285.8))]\\\\\Delta H_{rxn}=234.2J

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4 0
3 years ago
Exactly how many -OH groups are found in a 6 carbon alditol?
mr Goodwill [35]

Answer:

The number of  OH group found in found in a 6 carbon alditol is  6

Explanation:

The  structure of a 6 carbon alditol is shown on the first uploaded image

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