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nlexa [21]
3 years ago
14

Two students prepared aqueous solutions of LiCl and measured the properties, as shown in the table above. Both students observed

that the solid LiCl readily dissolved in H2O. The students drew particle diagrams to explain the changes in the enthalpy and entropy of dissolution for LiCl based on their results and observations. Based on this information, the better particle diagram was drawn by which student, and why is that diagram more accurate?
A) The better particle diagram was drawn by Student 1 because when LiCl dissolves in water, it dissociates into Li+ and Cl− ions causing an increase in entropy.

B) The better particle diagram was drawn by Student 1 because when LiCl dissolves in water, it dissociates into Li+ and Cl− ions indicating that the dissolution of LiCl is exothermic.

C) The better particle diagram was drawn by Student 2 because it shows that LiCl does not dissociate, resulting in a decrease in entropy for the dissolution of LiCl.

D) The better particle diagram was drawn by Student 2 because it shows that LiCl does not dissociate, resulting in an endothermic process for the dissolution of LiCl.
Chemistry
1 answer:
Shkiper50 [21]3 years ago
8 0

Answer:

c

Explanation:

it makes sense and the diagram is build like that with high tech

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Answer:

The change in internal energy of the heater is 0 kJ

Explanation:

∆U = Q - W

Q is quantity of heat transferred = 1 kJ

W is work done on the heater = 1 kJ

Change in internal energy (∆U) = 1 - 1 = 0 kJ

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an unknown amount of mercury (ii) oxide was decomposed in the lab. mercury metal was formed and 4.50 l of oxygen gas was release
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The initial weight of mercury oxide in the sample was 59.1 g HgO.

<h3>Steps</h3>

chemical reaction

2HgO ⟶ 2Hg + O₂

the moles of O₂

pV = nRT

n = (pV)/(RT)

Data:

p = 0.970 atm

V = 4.50 L

R = 0.082 06 L·atm·K⁻¹mol⁻¹

T = 390.0 K

Calculation:

n = (0.970 × 4.500)/(0.082 06 × 390.0)

n = 0.1364 mol O₂

the moles of HgO

The molar ratio is 1 mol O₂/2 mol HgO.

Moles of HgO = 0.1364 mol O₂ × (2 mol Hg/1 mol O₂)

Moles of HgO = 0.2728 mol HgO

the mass of HgO

Mass of HgO = 0.2728 mol HgO × (216.59 g HgO/1 mol HgO)

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For the creation of various organic mercury compounds and specific inorganic mercury salts, mercury(II) oxide, or HgO, serves as a source of elemental mercury.

This red or yellow crystalline substance is also utilised in mercury batteries and zinc-mercuric oxide electric cells as an electrode (combined with graphite).

<h3>What is the purpose of mercury oxide?</h3>

Mercuric oxide is a colourless, crystalline powder that ranges from yellow to orange-yellow.

It serves as a seed protectant, a pigment, a preservative, and an ingredient in alkaline batteries and cosmetics.

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2 years ago
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Answer:

The pH of the solution is 5.31.

Explanation:

Let "\alpha is the dissociation of weak acid - HCN.

The dissociation reaction of HCN is as follows.

                  HCN+H_{2}O\rightarrow H_{3}O^{+}+CN^{-}

Initial                  C                         0            0

Equilibrium        c(1- \alpha)              c\alpha c\alpha

Dissociation constant = Ka= c\alpha \times \frac{c\alpha}{c(1-\alpha)}

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In this case weak acids \alpha is very small so, (1-\alpha ) is taken as 1.

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From the given the concentration = 0.050 M

Substitute the given value.

\alpha=\sqrt\frac{4.9\times 10^{-10}}{0.05}=9.8\times 10^{-4}

[H_{3}O^{+}]=c\alpha

[H_{3}O^{+}]=0.05\times 9.8\times 10^{-4}= 4.9\times10^{-6}

pH= -log[H_{3}O^{+}]

=-log[4.9\times10^{-6}]

=6-log 4.9= 5.31

Therefore, The pH of the solution is 5.31.

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