Answer:
Add G and H to determine the atomic mass for helium
Explanation:
We can use the formula P=IV to calculate the current, where “P” is power (measured in watts), “I” is current (measured in Amps), and “V” is voltage. Simply plug and solve:
P = IV
(3.5 Watts) = I(120 volts)
I = 0.0292 Amps
The current flowing through the bulb is approximately 0.0292 Amps.
Hope this helps!
Answer:
C = 0.08M
Explanation:
molar mass of AlCl3
Al =27
Cl = 35.5
27+3(35.5) =133.5g/mol
n= mass/Molar mass
n =CV
CV = mass/molar mass
C x 500 x 10^-³ = 5/133.5
C x 500 x 10^-³ = 0.04
C = 0.04/500 x 10^-³
C = 0.08M
Answer: Lithium
Explanation:
The ratio for the reaction of Li and water is the same, but there are more moles of water than lithium. Therefore, lithium is the limiting reactant.
