Any charged object can<span> exert the force upon other objects ... i think tell me if im right</span>
Answer:
Energy: Kinetic, Sound, Thermal, gravitational, electric, light and nuclear
Explanation:
This exercise asks to clarify a little some important concepts
* Energy. It is the capable one that has the bodies to carry out a job.
* Kinetic energy. It is the energy due to the movement of objects
* sound energy. It is the energy due to the vibration of the atoms or molecules of the materials, it can be solid, liquid or gaseous
* Thermal energy. It is the energy due to movement of the particles
* Gravitational Energy. It is a configuration energy due to the height of the bodies with respect to a reference point
* Electric power. It is due to the movement of electric charges
* light energy. It is the energy that light carries due to the electric and magnetic fields that form it, it occurs throughout the electromagnetic spectrum
* Nuclear energy. It is the energy stored in the nucleus by the configuration and movement of protons and neutrons.
Answer:
Explanation:
A uniform circular motion is an example of accelerated motion.
When an object is moving in a uniform circular motion, there is a centripetal force acting towards the centre of the circular path and then a centrifugal force is also acting away from the centre of the circular path. The magnitude of the centripetal force and the centrifugal force is same but the direction is opposite to each other. So, it is explained by the Newton's third law.
<h3><u>Question</u><u>:</u></h3>
A racing car is travelling at 70 m/s and accelerates at -14 m/s^2. What would the car’s speed be after 3 s?
<h3><u>Statement:</u></h3>
A racing car is travelling at 70 m/s and accelerates at -14 m/s^2.
<h3><u>Solution</u><u>:</u></h3>
- Initial velocity (u) = 70 m/s
- Acceleration (a) = -14 m/s^2
- Time (t) = 3 s
- Let the velocity of the car after 3 s be v m/s
- By using the formula,
v = u + at, we have
- So, the velocity of the car after 3 s is 28 m/s.
<h3><u>Answer:</u></h3>
The car's speed after 3 s is 28 m/s.
Hope it helps
Recall this gas law:
= 
P₁ and P₂ are the initial and final pressures.
V₁ and V₂ are the initial and final volumes.
T₁ and T₂ are the initial and final temperatures.
Given values:
P₁ = 475kPa
V₁ = 4m³, V₂ = 6.5m³
T₁ = 290K, T₂ = 277K
Substitute the terms in the equation with the given values and solve for Pf:
<h3>P₂ = 279.2kPa</h3>
