Answer:


Step-by-step explanation:
Given




Required
Determine the number of miles driven on the highway and on the city
Represent the gallons used on highway with h and on city with c.
So, we have:
---- gallons used
and
--- distance travelled
In the first equation, make c the subject

Substitute 10 - h for c in the second equation


Open bracket

Collect like terms


Make h the subject


Substitute 5 for h in 


If on the highway, he travels 31 miles per gallon, then his distance on the highway is:


If in the highway, he travels 26 miles per gallon, then his distance on the highway is:


Answer:
I) |xz| ≈ 28.6 km
II) |yz| ≈ 34.8 km
Step-by-step explanation:
Let's assume that the position of ship due south of x is z (aà pictor representation of the question is attached)
|xy| = 20 km, |xz| = ?, |yz| = ?, θ(y) = 55°
Using Trigonometric ratio - SOHCAHTOA
I) Tan θ = |xz| ÷ |xy| ⇒ Tan 55° = |xz| ÷ 20
|xz| = 20 * Tan 55 = 20 * 1.428
|xz| = 28.56 km
|xz| ≈ <u>28.6 km</u>
<u />
II) Cos θ = |xy| ÷ |yz| ⇒ Cos 55° = 20 ÷ |yz|
|yz| * Cos 55° = 20 ⇒ |yz| = 20 ÷ Cos 55°
|yz| = 20 ÷ 0.574 = 34.84 km
|yz| ≈ <u>34.8 km</u>
Step-by-step explanation:
This is a right triangle with two congruent angles. so this is a isoceles right triangle or called a
45-45-90 triangle. This means that the legs are equal to each other so




Answer:
27
Step-by-step explanation: