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Vikki [24]
2 years ago
5

Geoffrey measures the width of his bedroom to determine the largest size bed frame he can have. The wall he plans to place the b

ed frame against is 13.65 feet wide. He wants there to be 2.25 feet between the wall and the bed frame on each side. What is the maximum width bed frame, in inches, that Geoffrey can put in his bedroom?
Mathematics
1 answer:
saw5 [17]2 years ago
8 0

Answer:109.8 inches

Step-by-step explanation:

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nadezda [96]
If you would like to know for how many days will 1/2 of a bag of dog food last, you can calculate this using the following steps:

1 day ... 3 bags of dog food
x days = ? ... 1/2 of a bag of dog food

1 * 1/2 = 3 * x
1/2 = 3 * x         /3
x = 1/2 * 1/3
x = 1/6 of a day

The correct result would be 1/6 of a day.
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2 years ago
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Musya8 [376]
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3 years ago
Find the simplified product b-5/2b x b^2+3b/b-5
White raven [17]

Answer:

The product \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}

Step-by-step explanation:

Given expression \frac{b-5}{2b} and \frac{b^2+3b}{b-5}

We have to find the product of  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}

   

Consider the given expression  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}

Multiply fractions, we have,

\frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d}

=\frac{\left(b-5\right)\left(b^2+3b\right)}{2b\left(b-5\right)}

Cancel common factor ( b - 5 )

we have, =\frac{b^2+3b}{2b}

Apply exponent rule,

\:a^{b+c}=a^ba^c

b^2=bb

=bb+3b=b(b+3)

=\frac{b\left(b+3\right)}{2b}

Cancel common factor b , we have,

=\frac{b+3}{2}

Thus, the product  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}

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olganol [36]

Answer:

new york

Step-by-step explanation:

0.79 pounds for a dollar costs less than 1.31 pounds for a dollar

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3 years ago
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