Answer:
your answer is b
Step-by-step explanation:
Answer: 12/18
Step-by-step explanation:
For a quick explanation, all you need to do is multiply 1/6 by 6 to get 1 whole and do the same to 2/3 so it’s proportional again.
Answer:
Step-by-step explanation:
Given the functions
F(x) = 6-x²
G(x) = x²+4x-12
A) we are to find F(x)+g(x)
F(x)+G(x) = 6-x²+x²+4x-12
F(x)+G(x) = 6+0+4x-12
F(x)+G(x) = 4x+6-12
F(x)+G(x) = 4x-6
The domain of the function is the values of x for which the expression exists. The expression exists on all real interval i.e xER
F(x)-g(x) = 6-x²-(x²+4x-12)
F(x)-g(x) = 6-x²-x²-4x+12
F(x)-g(x) = 6-2x²+4x+12
F(x)-g(x) = -2x²+4x+6
The domain of the function is the values of x for which the expression exists. The expression exists on all real interval i.e xER
3) F(x)/G(x)
= 6-x²/x²+4x-12
The domain of the function is the values of x for which the expression exists. The expression exists on all real interval i.e xER
Answer:
x = 5 /2 , y = 9 / 8
Step-by-step explanation:
x = 4y - 2 ....... (i)
x + 4y =7 ....... (ii)
Substituting eqn (i) into eqn (ii);
(4y - 2 ) + 4y = 7
4y - 2 + 4y = 7
8y = 7 + 2 = 9
y = 9 / 8
substitute y = 9 / 8 in eqn (i)
x = 4 (9 / 8) - 2
x = 9 / 2 - 2
x = (9 - 4 ) / 2
x = 5 / 2
