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Step-by-step explanation:
Let the side of the garden alone (without walkway) be x.
Then the area of the garden alone is x^2.
The walkway is made up as follows:
1) four rectangles of width 2 feet and length x, and
2) four squares, each of area 2^2 square feet.
The total walkway area is thus x^2 + 4(2^2) + 4(x*2).
We want to find the dimensions of the garden. To do this, we need to find the value of x.
Let's sum up the garden dimensions and the walkway dimensions:
x^2 + 4(2^2) + 4(x*2) = 196 sq ft
x^2 + 16 + 8x = 196 sq ft
x^2 + 8x - 180 = 0
(x-10(x+18) = 0
x=10 or x=-18. We must discard x=-18, since the side length can't be negative. We are left with x = 10 feet.
The garden dimensions are (10 feet)^2, or 100 square feet.
<span>(f o g)(-4)
=-4(3x+5)+7
</span><span>=-4(3(-4)+5)+7</span><span>
= 35</span>
It has to be 5 because 2.5 is half so the other half 2.5 .so 2.5 +2.5 =5
Answer:
The zeros are -1, 0, and 2
Step-by-step explanation:
The zeroes of f are the points where the graph f crosses the x-axis, which occur at x = -2, x = 0, x = 2.
Have a great day :)
