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Firlakuza [10]
2 years ago
7

We want to find the zeros of this polynomial: p(x) = (x+2) (2x^2 + 3x-9)

Mathematics
1 answer:
lorasvet [3.4K]2 years ago
3 0

Answer:

x = - 2, x = - 3, x = \frac{3}{2}

Step-by-step explanation:

to find the zeros equate p(x) to zero , then

(x + 2)(2x² + 3x - 9) = 0 ← factor the quadratic

(x + 2)(x + 3)(2x - 3) = 0

equate each factor to zero and solve for x

x + 2 = 0 ⇒ x = - 2

x + 3 = 0 ⇒ x = - 3

2x - 3 = 0 ⇒ 2x = 3 ⇒ x = \frac{3}{2}

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<h3>Equation of a function</h3>

The nth term of an arithmetic progression is expressed as;

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Learn more on nth term of an AP here: brainly.com/question/19296260

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