Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)
If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.
On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.
For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.
Then the range of F(x) is the interval [-π, π].
The answer is (-3,4) your welcome
Answer:
I’m not sure. If your joking or.
For a.
Since there are already two angles given for the triangle, we can measure the last angle using this formula:
90 + 55 + a = 180
Now solve for "a".
90 + 55 + a = 180
145 + a = 180
a = 180 - 145
a = 35°
For b.
From the picture above, the two triangle's tip are touching and having to form <em>vertical angles. </em>This means that the angles are congruent to each other.
Now that we have two angles in the second triangle(35 and 120), we can use the same formula:
35 + 120 + b = 180
Now solve for "b":
35 + 120 + b = 180
155 + b = 180
b = 180 - 155
b = 25°
Answer:
What will help is labeling the diagram with the given info..A proof always ends with the statement you have to prove.
Step-by-step explanation:
STATEMENT..............REASON
1) ∠F≅∠C 1) Given
2) E is the midpoint of GD 2) Given
3) GE≅ED 3) If a point is a midpoint then 2 ≅ segments are formed
4) FE≅EC 4) Same as 3
5)∠G≅∠D 5)
6) FG≅CD 6)
I tried my best with step 5 and 6..but you know step 6 has to be the prove statement but i don't know what the reason would be. I hope i helped a bit though.
