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V125BC [204]
2 years ago
5

What is 122 / 600?

600" align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
kipiarov [429]2 years ago
5 0
The answer : 0.20333333333
dmitriy555 [2]2 years ago
4 0

Answer:

122÷600

0.203333334

that's my answer please

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Identify the base in this statement:<br> 16% of 98 is 15.68
Darya [45]

Ans: The base in the statement “16% of 98 is 15.68” is 98.

The three quantities in problems involving percent are Percent, Base, amount. ‘Percent’ has the percent (%) symbol. The base is the whole amount and the amount is the amount which comes after calculation the percent of the total amount.

So, in above problem, total amount i.e. Base is 98

Percent is 16%

And, the amount is 15.68.

<span>Moreover, the base in the statement comes after the word ‘of’ and in above statement, the digit after ‘of’ is 98.</span>

6 0
3 years ago
Marty teaches music in his community. He teaches three classes a day, and each class has fewer than 8 students. If Marty teaches
Molodets [167]
It is c becase x<8 translates to x is less than 8
8 0
3 years ago
How many terms can 5x+9-4b have
Nikolay [14]

Answer:

8x

Step-by-step explanation:

The constants are the numbers that are NOT

attached to anything. In the expression, 3x + 2,

(2) is a constant because it is not attached to

anything. The (3) is not a constant because it

is attached to x, and it is actually a coefficient.

4 0
3 years ago
Write the equation for a line that has an initial value of 3 and 3/4 as it’s rate of change
frutty [35]

the slope goes by several names

• average rate of change

• rate of change

• deltaY over deltaX

• Δy over Δx

• rise over run

• gradient

• constant of proportionality

however, is the same cat wearing different costumes.

initial value of 3, namely when x = 0, y = 3, so we have the point (0 , 3) and it has a rate or slope of 3/4.

(\stackrel{x_1}{0}~,~\stackrel{y_1}{3})\qquad \qquad \stackrel{slope}{m}\implies \cfrac{3}{4} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{\cfrac{3}{4}}(x-\stackrel{x_1}{0})\implies y=\cfrac{3}{4}x+3

3 0
2 years ago
On any given day, the number of users, u, that access a certain website can be represented by the inequality 125-4530
Masteriza [31]

Answer:

Step-by-step explanation:

Our inequality is |125-u| ≤ 30. Let's separate this into two. Assuming that (125-u) is positive, we have 125-u ≤ 30, and if we assume that it's negative, we'd have -(125-u)≤30, or u-125≤30.

Therefore, we now have two inequalities to solve for:

125-u ≤ 30

u-125≤30

For the first one, we can subtract 125 and add u to both sides, resulting in

0 ≤ u-95, or 95≤u. Therefore, that is our first inequality.

The second one can be figured out by adding 125 to both sides, so u ≤ 155.

Remember that we took these two inequalities from an absolute value -- as a result, they BOTH must be true in order for the original inequality to be true. Therefore,

u ≥ 95

and

u ≤ 155

combine to be

95 ≤ u ≤ 155, or the 4th option

4 0
3 years ago
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