Water molecules are made of hydrogen atoms and one oxygen atom.
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Answer:
Instrumental methods
surface analysis
high performance liquid chromatography
atomic spectroscopy
potentiometry
Classical methods
precipitation titration
gravimetric analysis
Explanation:
Instrumental methods of analysis are those analytical methods in which the responsibility of detection has been removed from human beings and placed on automated instruments while classical methods are those analytical methods in which the responsibility of detection remains the responsibility of human beings.
Many instrumental methods such as HPLC rely on computer screens as readout devices.
Answer : the statement that is true about the atom is It is present in the second group of the periodic table.
Explanation :
The Lewis dot model shows the number of valence electrons present in the atom.
Since the given metal has 2 dots, it indicates that the metal atom must have 2 electrons in its outermost shell.
Therefore option 2 : It has two electrons in the innermost energy level, is wrong because it contains 2 electrons in the outermost energy level
Option 1 : It is most likely to form covalent bonds is also wrong because a metal atom always forms ionic bond
Option 3 : It requires six other atoms to form a stable compound, is also wrong as the metal can form a stable compound by donating its 2 electrons to a non metal.
On periodic table, representative elements are arranged in groups based on their valence electrons. Therefore by knowing the outermost electrons, we can predict the group in which the element can be categorized.
Since the given metal atom contains 2 electrons, it must be present is second group.
Therefore the statement that is true about the atom is It is present in the second group of the periodic table.
Answer:
Explanation:
An iodide ion is the ion I−. Compounds with iodine in formal oxidation state −1 are called iodides.
Answer:
Net NADH = zero
Explanation:
1 mole glucose
=6.02×10^23molecules
=6.02×10^23 × 2
pyruvates + 2 NADH
43 moles of glucose
= 43×12.04×10^23pyruvates
+43×12.04×10^23NADH
2pyruvates uses 2 NADH molecules
43×12.04×10^23 will use 43×12.04×10^23NADH
Hence net NADH produce is zero.
Which means NADH formed during glucose to pyruvate conversion is utilised during fermentation to regenerate NAD+
