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2 years ago

George has a mass of 65kg. What would George weigh on the Moon? (The gravitational field strength on the Moon is 1.6N/kg.)

Chemistry

2 answers:

sergey [27]2 years ago

8 0

Answer:

The weight of George on Moon is 104 N

Explanation:

Weight is called the action exerted by the force of gravity on the body.

The mass (amount of matter that a body contains) of an object will always be the same, regardless of where it is located. Instead, the weight of the object will vary according to the force of gravity acting on it.

The formula that allows you to calculate the weight of any body is:

P = m * g

where:

P = weight measured in N.

m = mass measured in kg.

g = acceleration of gravity measured in m / s²

But in this case the weight of George on the moon can be calculated as the mass of George multiplied by the intensity of the gravitational field.

weight of George on Moon = George's Mass*Gravitational field strength

$weight of George on Moon=65 kg* 1.6 \frac{N}{kg}$

weight of George on Moon=104 N

So <u><em>the weight of George on Moon is 104 N</em></u>

dem82 [27]2 years ago

5 0

Answer:

$\boxed{\large \text{104 N}}$

Explanation:

$\text{Weight} = \text{65 kg} \times \dfrac{\text{1.6 N}}{\text{1 kg}} = \textbf{104 N}\\\\\text{George would weigh $\boxed{\large \textbf{104 N}}$ on the moon}$

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For each pair, predict which molecule has the greater molar entropy under the same conditions (assume gaseous species).c o 2, ca

larisa [96]

I used to know this. I don't really remember but is used to know it. Im in 6th grade now

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3 years ago

Solution A is 0.44 M and reacts with 0.11 M of solution B. Assume that the value of x is 0, the value of y is 1, and r is 1.07 ×

xz_007 [3.2K]

Answer:

K, the rate constant = 9.73 × 10^(-1)/s

Explanation:

r = K × [A]^x × [B]^y

r = Rate = 1.07 × 10^(-1)/s

K = Rate constant

A and B = Concentration in mol/dm^-3

A = 0.44M

B = 0.11M

x = Order of reaction with respect to A = 0

y = Order of reaction with respect to B = 1

Solving, we get

r/([A]^x × [B]^y) = K

K = 1.07 × 10^(-1)/s/(0.44^0 × 0.11^1)= 0.9727

K = 0.9727

7 0

3 years ago

FORENSIC SCIENCE HELP

Annette [7]

That is correct c
Explanation

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2 years ago

What is 2.75 mol of O2

ANTONII [103]

Answer:

2,75 mol of O2 it's 88 g of O2.

Explanation:

The weight of the diatomic molecule O2 is 32 g/mol. So considering that, you should multiply 2,75 mol · 32 = 88g :)

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2 years ago

When nahco3 completely decomposes, it can follow this balanced chemical equation: 2nahco3 → na2co3 h2co3 determine the theoretic

BigorU [14]

Theoretical yield = 2.397

The product could be sodium carbonate

percent yield = 98.456%

When nahco3 completely decomposes, it can follow this balanced chemical equation:

2nahco3 → na2co3 h2co3

If the mass of the NaHCO3 sample is 3.80 g, we must use stoichiometry to calculate the theoretical yields of each of the products.

mass of NaHCO₃ = 3.80 g

molar mass of NaHCO₃ = 84 g/mol

so the no of moles of NaHCO₃ = 3.80/84 = 0.0452 mol

You see, one mole of sodium carbonate and one mole of hydrogen carbonate are produced from two moles of sodium bicarbonate.

so, the no of moles of sodium carbonate = 0.0452/2 = 0.0226 mol

∴ mass of sodium carbonate ( Na₂CO₃) = no of moles of Na₂CO₃ × molar mass of Na₂CO₃

= 0.0226 × 106 ≈ 2.397 g

no of moles of hydrogen carbonate = 0.0452/2 = 0.0226 mol

mass of the hydrogen carbonate ( H₂CO₃) = no of moles of H₂CO₃ × molar mass of H₂CO₃

= 0.0226 × 62 g = 1.401 g

mass of one of the products was measured to be 2.36 g , from above data, we can say it must be sodium carbonate because value is the nearest of 2.397 g.

percentage yield = experimental yield/theoretical yield × 100

here experimental yield of Na₂CO₃ = 2.36 g

and theoretical yield of Na₂CO₃ = 2.397 g

∴ % yield = 2.36/2.397 × 100 ≈ 98.456%

Therefore the percentage yield of the product is 98.456%

To learn more about percentage yield visit:

brainly.com/question/22257659

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6 0

1 year ago