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melisa1 [442]
3 years ago
7

George has a mass of 65kg. What would George weigh on the Moon? (The gravitational field strength on the Moon is 1.6N/kg.)

Chemistry
2 answers:
sergey [27]3 years ago
8 0

Answer:

The weight of George on Moon is 104 N

Explanation:

Weight is called the action exerted by the force of gravity on the body.

The mass (amount of matter that a body contains) of an object will always be the same, regardless of where it is located. Instead, the weight of the object will vary according to the force of gravity acting on it.

The formula that allows you to calculate the weight of any body is:

P = m * g

where:

P = weight measured in N.

m = mass measured in kg.

g = acceleration of gravity measured in m / s²

But in this case the weight of George on the moon can be calculated as the mass of George multiplied by the intensity of the gravitational field.

weight of George on Moon = George's Mass*Gravitational field strength

weight of George on Moon=65 kg* 1.6 \frac{N}{kg}

weight of George on Moon=104 N

So <u><em>the weight of George on Moon is 104 N</em></u>

dem82 [27]3 years ago
5 0

Answer:

\boxed{\large \text{104 N}}  

Explanation:

\text{Weight} = \text{65 kg} \times \dfrac{\text{1.6 N}}{\text{1 kg}} = \textbf{104 N}\\\\\text{George would weigh $\boxed{\large \textbf{104 N}}$ on the moon}

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773.33 degrees F
F=Fahrenheit
K=Kelvin
F=K x 9/5 - 459.67
773.33 = 685 x 9/5 - 459.67

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3 years ago
The density of NaCl( s) is 2.165 g cm 3 at 25 C. How will the solubility of NaCl in water be affected by an increase in pressure
sammy [17]

The solubility of NaCl in water will not be affected by an increase in pressure.

We know that the density of NaCl(s) in 2.165 g/cm³ at 25 °C and we want to know how will its solubility in water be affected when the pressure is increased.

<h3>What is solubility?</h3>

Solubility is the maximum mass of a solute that can be dissolved in 100 grams of solvent at a determined temperature.

The solubility of a solid, such as NaCl, in a liquid, is mainly affected by the temperature. However, since solids are not compressible, an increase in pressure will not affect its solubility.

On the other hand, the solubility of gases in water will increase with an increase in pressure, as stated by Henry's law.

The solubility of NaCl in water will not be affected by an increase in pressure.

Learn more about solubility here: brainly.com/question/11963573

7 0
2 years ago
PLS HELP ME I HAVE TILL 12
MariettaO [177]

Answer:

alright bud lets see hmm.... the answer is a. 90.5kpa

Explanation:

92.3 kPa - 1.82 kPa = 90.5 kPa

keep up your hope also corrected me if a am wrong in anyway! :)

3 0
3 years ago
2C2H2(g)+5O2(g)=4CO2(g)+2H2O(g)
balandron [24]

The volume of ethyne, C₂H₂ required to produce 12 moles of CO₂ assuming the reaction is at STP is 134.4 L

<h3>Balanced equation</h3>

2C₂H₂(g) + 5O₂(g) --> 4CO₂(g) + 2H₂O(g)

From the balanced equation above,

4 moles of CO₂ were produced by 2 moles of C₂H₂

<h3>How to determine the mole of C₂H₂ needed to produce 12 moles of CO₂</h3>

From the balanced equation above,

4 moles of CO₂ were produced by 2 moles of C₂H₂

Therefore,

12 moles of CO₂ will be produce by = (12 × 2) / 4 = 6 moles of C₂H₂

<h3>How to determine the volume (in L) of C₂H₂ needed at STP</h3>

At standard temperature and pressure (STP),

1 mole of C₂H₂ = 22.4 L

Therefore,

6 moles of C₂H₂ = 6 × 22.4

6 moles of C₂H₂ = 134.4 L

Thus, we can conclude that the volume of C₂H₂ needed for the reaction at STP is 134.4 L

Learn more about stoichiometry:

brainly.com/question/14735801

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3 0
2 years ago
How much of strontium-90 will be left after 40 hours if you start with 960 grams and the half-life is 10 hours?
zmey [24]

Answer:

5 hours

Explanation:

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