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3 years ago

For a reaction 2A + B 2C, with the rate equation: Rate = k[A]2[B]

1 answer:

3 0

For reaction

2 A + B ------------> 2 C

Rate = K [ A ]² [ B ]

 the order with respect to A is 2 and the order overall is 3.

hope this helps!

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What is the pOH of 0.50 molar H3BO3?

Crazy boy [7]

Answer:

A. 10.25

Explanation:

Pkb =4.77

So pka = 14 - pka = 9.23

$Ka =10^{-pka}$

$H_3 BO_3 (aq)+ H_2 O(l) H_2 BO_3^- (aq)+H_3 O^+ (aq)$

Initial 0.50M 0 0

Change -x +x +x

Equilibrium 0.50M-x +x +x

$Ka =\frac {((x)(x))}{(0.50M-x)}$

$5.88\times10^{-10}= \frac {x^2}{(0.50M-x)}$

(-x is neglected) so we get

$5.88\times10^{-10}\times0.50=x^2\\\\x^2=2.94\times10^{-10}$

$x=\sqrt{x^2}=1.72\times10^{-5} M=H^3 O^{+}$

$pH=-log[H^3 O^+]\\\\pH=-log[1.72\times10^{-5}]\\\\pH=4.76$

pOH = 14 - pH

= 14 - 4.76

pOH = 9.24 is the answer

Option A - 10.25 is the answer which is close to 9.24

4 0

3 years ago

Potassium hydrogen phthalate, KHP, is a monoprotic acid often used to standardize NaOH solutions. If 0.212 g of KHP are dissolve

pochemuha

0.212 g of KHP is are dissolved in 50.00 mL of water and are titrated by 35.00 mL of 0.0297 M NaOH.

Potassium hydrogen phthalate, KHP, is a monoprotic acid often used to standardize NaOH solutions.

The balanced neutralization equation is:

NaOH(aq) + KHC₈H₄O₄(aq) ⇒ KNaC₈H₄O₄(aq) + H₂O(l)

Step 1: Calculate the reacting moles of KHP.

0.212 g of KHP react. The molar mass of KHP is 204.22 g/mol.

0.212 g × 1 mol/204.22 g = 1.04 × 10⁻³ mol

Step 2: Determine the reacting moles of NaOH.

The molar ratio of NaOH to KHP is 1:1.

1.04 × 10⁻³ mol KHP × 1 mol NaOH/1 mol KHP = 1.04 × 10⁻³ mol NaOH

Step 3: Calculate the molarity of NaOH.

1.04 × 10⁻³ moles of NaOH are in 35.00 mL of solution.

[NaOH] = 1.04 × 10⁻³ mol / 35.00 × 10⁻³ L = 0.0297 M

0.212 g of KHP is are dissolved in 50.00 mL of water and are titrated by 35.00 mL of 0.0297 M NaOH.

Learn more about titration here: brainly.com/question/4225093

3 0

2 years ago

Consider the following reaction at equilibrium: 2 NH3(g) ⇄ N2(g) + 3 H2(g) What does Le Chatelier's principle predict will happe

BabaBlast [244]

Answer : The equilibrium will shift in the left direction.

Explanation :

Le-Chatelier's principle : This principle states that if any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

The given reaction is:

$2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)$

As per question, when we are adding $N_2$ then the concentration of $N_2$ is increased on product side then the equilibrium will shift in the direction where decrease of concentration of $N_2$ takes place. Therefore, the equilibrium will shift in the left direction.

Thus, the equilibrium will shift in the left direction.

7 0

3 years ago

What happens if a geologist drips a small amount of vinegar (acetic acid) onto a sample of dolomite?

Lapatulllka [165]

Hydrochloric acid on a rock or mineral and watching for bubbles of carbon dioxide gas to be released. The bubbles signal the presence of carbonate minerals such as calcite and dolomite.

4 0

3 years ago

Why is it important to minimize the amount of oil released into the ocean?

Andrei [34K]

Because many animals are likely to die from contamination

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3 years ago