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krok68 [10]
2 years ago
9

Help pls ASAP thank you!!

Chemistry
1 answer:
BigorU [14]2 years ago
5 0

Answer:

Deer, Eagle, Raccoon, frog, turtle, fish, dragonfly.

Explanation:

They interact from the life cycle they eat each other...

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In this thermochemical reaction, what does the coefficient ½ represent?
timurjin [86]
A thermochemical reaction is a chemical reaction with an additional information of the heat of reaction. For example, this is the thermochemical reaction for the combustion of hydrogen gas:

H₂ (g) + 1/2 O₂ (g) → H₂O (l)         ΔH = -285.8 kJ

The coefficient 1/2 represents the number of moles of O₂ needed to combust 1 mole of H₂ gas in order to yield one mole of water.
3 0
3 years ago
HELP 20 Points? thank u guysssss
Fudgin [204]

Answer:

The answer is A. Chemical

Explanation:

Have a nice day

3 0
3 years ago
Read 2 more answers
How many CO2 molecules in 0.0189 mol of CO2?
Blizzard [7]

Answer:

option C is correct = 1.14 × 10²² molecules of  CO₂

Explanation:

Given data:

Number of moles of CO₂ = 0.0189 mol

Number of molecules = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

For given question:

1 mole of CO₂ =  6.022 × 10²³ molecules of  CO₂

0.0189 mol of CO₂ ×  6.022 × 10²³ molecules of  CO₂ / 1mol

1.14 × 10²² molecules of  CO₂

Thus, option C is correct.

4 0
3 years ago
Fabric is made of ___​
GuDViN [60]

Answer:

Fabric is made of cotton.

Explanation:

Hope that helps :)

6 0
3 years ago
Read 2 more answers
In uncompetitive inhibition, the inhibitor can bind to the enzyme only after the substrate binds first. (T/F)
Veronika [31]

Answer:

True

Explanation:

In an uncompetitive inhibition, initially the substrate [S] binds to the active site of the enzyme [E] and forms an enzyme-substrate activated complex [ES].

The inhibitor molecule then binds to the enzyme- substrate complex [ES], resulting in the formation of [ESI] complex, thereby inhibiting the reaction.

This inhibition is called uncompetitive because the inhibitor does not compete with the substrate to bind on the active site of the enzyme.

Therefore, in an uncompetitive inhibition, the inhibitor molecule can not bind on the active site of the enzyme directly. The inhibitor can only bind to the enzyme-substrate complex formed.

       

4 0
2 years ago
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