1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sindrei [870]
2 years ago
6

Suppose a grower sprays (8.2x10^1) kg of water at 0 °C onto a fruit tree of mass 180 kg. How much heat is released by the water

when it freezes?
Physics
1 answer:
____ [38]2 years ago
6 0

Since there is no temperature change which drives heat flow, thus no heat will be released by the water.

<h3>Heat released by the water when it freezes</h3>

The heat released by the water when it freezes is calculated as follows;

Q = mcΔФ

where;

  • m is mass of water
  • c is specific heat capacity of water
  • ΔФ is change in temperature = Фf - Фi

when water freezes, the temperature, Фf = 0 °C

Q = 82 x 4200 x (0 - 0)

Q = 0

Since there is no temperature change which drives heat flow, thus no heat will be released by the water.

Learn more about heat flow here: brainly.com/question/14437874

You might be interested in
Which question cannot be answered through making measurements?
Bond [772]
A. is the answer for this question
5 0
3 years ago
Parents have a major role in observing how young children grow at home. Create and discuss simple developmental monitoring tips
Rudik [331]

Answer:

by observation of their children

4 0
2 years ago
What force must the worker exert to get the box moving &amp; what force must the worker exert to accelerate the box at 0.1 meter
photoshop1234 [79]

Since static friction is the minimum force required to just start the motion of a stationary object.

Here if we need to start an object from rest then we required F = 700 N

So for the first part of the above problem Force will be F = 700 N

Now if the box is already moving then we will have to use kinetic friction force between box and floor

now we can write the equation of net force as

F - F_k = m*a

here

F_k = kinetic friction = 220 N

m = mass = 500 kg

a = acceleration = 0.1 m/s^2

now we will have

F - 220 = 500* 0.1

F = 220 + 50 = 270 N

3 0
3 years ago
What affect does an increase in the angle of incidence have upon the angle of reflection?
valentina_108 [34]
????????????? ??????????????????? ?????????????????
6 0
3 years ago
What two statements are true about energy transformations
Arisa [49]

Answer:

First statement:

Energy can neither be created nor destroyed.

Second statement:

Energy can be converted from one form to another.

Explanation:

According to the law of conservation of energy:energy can neither be created nor destroyed but can be converted from one form to another

4 0
3 years ago
Other questions:
  • The relationship between frequency wavelength and speed holds for light waves because
    5·1 answer
  • Which of the following statements correctly describe the various forms of EM radiation listed above?A) They have different wavel
    7·1 answer
  • An uncovered pot of soup is simmering on a stove, and there are water droplets on the wall above the back of the stove. what seq
    5·2 answers
  • Which of the following cannot be the result of punctuated equilibrium
    11·1 answer
  • What is Parabolic flight
    7·2 answers
  • What is the mass of a cannonball if a force of 2,500 N gives the cannonball an acceleration of 200m/s2?
    10·2 answers
  • Who was the first scientist to propose that an object could emit only certain amounts of energy?
    5·1 answer
  • A person tosses a ball from the ground up into the air at an initial speed of 10 m/sec and an initial angle of 43◦ off the groun
    8·1 answer
  • You are standing next to a table and looking down on a record player sitting on the table. Take the spindle (axis of rotation) t
    15·1 answer
  • An electric pump has 2kW power . How much water will it lift every minute if the height is 10 m ?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!