Options:
a) 10 m/s²
b) 8 m/s²
c) 4.4 m/s²
d) More information is needed
Answer:
d) More information is needed
Explanation:
The acceleration due to gravity at an altitude h above the surface of a planet is given by the equation:
.................(1)
where the altitude above the surface of the planet X, h = 3000 km
Acceleration due to gravity at the surface of the planet, g₀ = 10 m/s²
To be able to get the acceleration due to gravity, g, at an altitude h above the surface of the planet, all parameters must be substituted into equation (1).
Unfortunately, the radius, R, of the planet, X, is not given. This means that there are no sufficient parameters(information) to find the acceleration due to gravity at an altitude h above the surface of the planet.
Answer:
0 MN/C, 2.697 MV
4.1953 MN/C, 1.2586 MV
19.2642857143 MN/C, 2.697 MV
Explanation:
k = Coulomb constant =
Electric field at r = 8 cm
E = 0 (inside)
Electric potential is given by
Electric potential is 2.697 MV
r = 30 cm
Electric field is 4.1953 MN/C
Electric potential is 1.2586 MV
r = R = 14 cm
The electric field is 19.2642857143 MN/C
The potential is 2.697 MV
Answer:
dt/dx = -0.373702
dt/dy = -1.121107
Explanation:
Given data
T(x, y) = 54/(7 + x² + y²)
to find out
rate of change of temperature with respect to distance
solution
we know function
T(x, y) = 54 /( 7 + x² + y²)
so derivative it x and y direction i.e
dt/dx = -54× 2x / (7 +x² + y²)² .........................1
dt/dy = -54× 2y / (7 + x² + y²)² .........................2
now put the value point (1,3) as x = 1 and y = 3 in equation 1 and 2
dt/dx = -54× 2(1) / (7 +(1)² + (3)²)²
dt/dx = -0.373702
and
dt/dy = -54× 2(3) / (7 + (1)² + (3)²)²
dt/dy = -1.121107
Convection- electromagnetic waves
radiation- heat energy from the Sun
thermal expansion- sea levels rising
vacuum- vacuum cleaner
heat engine- steam engine
convection current - molten rock
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