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alex41 [277]
3 years ago
8

In a third class lever, the distance from the effort to the fulcrum is ____________ the distance from the load/resistance to the

fulcrum.
Physics
1 answer:
padilas [110]3 years ago
4 0
The complete sentence is:
In a third class lever, the distance from the effort to the fulcrum is SMALLER the distance from the load/resistance to the fulcrum.
In fact, in a third class lever, the fulcrum is on one side of the effort and the load/resistance is on the other side, so the effort is located somewhere between the two of them. This means that the distance effort-fulcrum is smaller than the distance load-fulcrum.
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Firdavs [7]

Initial velocity (u) = 2 m/s

Acceleration (a) = 10 m/s^2

Time taken (t) = 4 s

Let the final velocity be v.

By using the equation,

v = u + at, we get

or, v = 2 + 10 × 4

or, v = 2 + 40

or, v = 42

The final velocity is 42 m/s.

5 0
2 years ago
Read 2 more answers
Frying an egg conduction convention radiation
Allushta [10]

Answer:

frying an egg is conduction because the pan is touching the stove and the pan is touching the eggs

Explanation:

4 0
3 years ago
A rocket is fired at 100 m/s at an angle of 37, how many seconds did it take to get to the top?
Kobotan [32]

Answer:

6.14 s

Explanation:

The time the rocket takes to reach the top is only determined from its vertical motion.

The initial vertical velocity of the rocket is:

u_y = u sin \theta = (100)(sin 37^{\circ})=60.2 m/s

where

u = 100 m/s is the initial speed

\theta=37^{\circ} is the angle of launch

Now we can apply the suvat equation for an object in free-fall:

v_y = u_y +gt

where

v_y is the vertical velocity at time t

g=-9.8 m/s^2 is the acceleration of gravity

The rocket reaches the top when

v_y =0

So by substituting into the equation, we find the time t at which this happens:

t=-\frac{u_y}{g}=-\frac{60.2}{-9.8}=6.14 s

7 0
3 years ago
A hydrogen atom in the n=7 state decays to the n=4 state. what is the wavelength of the photon that the hydrogen atom emits? use
frez [133]

A hydrogen atom in the n=7 state decays to the n=4 state. The wavelength of the photon that the hydrogen atom emits is 4592.59nm.

The Energy of photon is the energy possessed by a photon when it moves from a high energy level to a low energy level. It emits a photon of a certain wavelength. The following relation can be used to find out the relation between the energy levels and the energy possessed:

E = 13.6 × Z² (1/n₂² - 1/n₁²) eV

where, n₁ is the initial energy level i.e. n₁ =7

            n₂ is the higher energy level i.e. n₂ = 4

            E is the energy possessed

            Z is the atomic number, Z = 1 for H-atom

Subsituting in above equation,

E = 13.6 (1/16 - 1/49) eV

E = 0.27 eV

We know that,

E = hc / λ  

where, h is Planck constant

           c is speed of light

            λ is wavelength

On subsituting,

0.27 eV = 1240/ λ

⇒ λ = 4592.59 nm

Hence, the wavelength of photon emitted by Hydrogen atom is 4592.59nm.

Learn more about Energy of Photon here, brainly.com/question/2393994

#SPJ4

 

5 0
2 years ago
When you stand outside your are standing in the, Stratosphere. Troposphere. Mesosphere no
AVprozaik [17]
Uhhh I’m not really sure of the answer i think it’s stratosphere
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