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neonofarm [45]
3 years ago
15

A ball at rest starts rolling down a hill with a constant acceleration of 3.2 meters/second. What is the final velocity of the b

all after 6.0 seconds?
Physics
1 answer:
a_sh-v [17]3 years ago
5 0
19.2 meters/second^2 would be the correct answer.

Try multiplying 3.2 meters/second^2 by 6 and you will receive the answer provided above. If you have any further questions, let me know!
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Calculate the kinetic energy, in joules of a 1160-kg automobile moving at 19.0 m/s.
Rudiy27

Answer:

Explanation:

K.E=1/2 mv²

m=1160 kg

v=19.0 m/s

so k.e=1/2*1160*(19.0)²

K.E=1/2*1160*361

K.E=1/2*418760

K.E=209380=2.0*10^5 j

7 0
3 years ago
Which type of energy is the original source for the energy that food molecules can provide?
Svet_ta [14]

Answer:

Chemical potential energy

Explanation:

which is used to for any form of energy.

4 0
3 years ago
Roseanne heated a solution in a beaker as part of a laboratory experiment on energy transfer. After a while, she noticed the liq
Anna35 [415]
Water boilingis the answer
5 0
3 years ago
A 6 N and a 10 N force act on an object. The moment arm of the 6 N force is 0.2 m. If the 10 N force produces five times the tor
Levart [38]

Answer:

The moment arm is 0.6 m

Explanation:

Given that,

First force F_{1}=6\ N

Second force F_{2}=10\ N

Distance r = 0.2 m

We need to calculate the moment arm

Using formula of torque

\tau=Force\times lever\ arm

So, Here,

\tau_{2}=5 \tau_{1}

We know that,

The torque is the product of the force and distance.

Put the value of torque in the equation

F_{2}\times d_{2}=5\times F_{1}\times r_{1}

r_{2}=\dfrac{5\times F_{1}\times r_{1}}{F_{2}}

Where, F_{1}=First force

F_{1}=First force

F_{2}=Second force

r_{1}= distance

Put the value into the formula

r_{2}=\dfrac{5\times6\times0.2}{10}

r_{2}=0.6\ m

Hence, The moment arm is 0.6 m

6 0
3 years ago
How many seconds will it take for a satellite to travel 450,000 m at a rate of 120 m/s?
V125BC [204]
3750 seconds to travel that far
5 0
3 years ago
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