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neonofarm [45]
3 years ago
15

A ball at rest starts rolling down a hill with a constant acceleration of 3.2 meters/second. What is the final velocity of the b

all after 6.0 seconds?
Physics
1 answer:
a_sh-v [17]3 years ago
5 0
19.2 meters/second^2 would be the correct answer.

Try multiplying 3.2 meters/second^2 by 6 and you will receive the answer provided above. If you have any further questions, let me know!
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Not that simple but there are ways. Just make sure your hands can handle it
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2 years ago
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A transverse wave on a string is described by the wave function
svp [43]

The period of the transverse wave from what we have here is 0.5

<h3>How to find the period of the transverse wave</h3>

The period of a wave can be defined as the time that it would take for the wave to complete one complete vibrational cycle.

The formula with which to get the period is

w = 4π

where w = 4 x 22/7

2π/T = 4π

6.2857/T = 12.57

From here we would have to cross multiply

6.2857 = 12.57T

divide through by 12.57

6.2857/12.57 = T

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Hence we can conclude that the value of T that can determine the period based on the question is 0.500.

Read more on transverse wave here

brainly.com/question/2516098

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5 0
1 year ago
A ball is dropped off the balcony of a hotel room and it takes 2.8s to fall to the ground . how high above the ground is the bal
RideAnS [48]

The height of the ball above the ground is 38.45 m

First we will calculate the velocity of the ball when it touch the ground by using first equation of motion

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v=0+9.81×2.8

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now the height of the ground can be calculated by the formula

v=√2gh

27.468=√2×9.81×h

h=38.45 m

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2 years ago
If the moon is rising at midnight, the phase of the moon must be
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The phase is called 3rd quarter.

Hope this helps:)
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3 years ago
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