Answer:
Explanation:
The distance of a fringe from centre is proportional to wavelength of light
and inversely proportional to separation of slits. The expression for distance x is given by
x = nλ D / d
where λ is wave length , D is screen distance and d is slit separation.
So first option only is correct because
1 ) the wavelength of blue light is less than that of red
2) Intensity of light does not affect distance of fringe from the centre.
3.
Diffraction symbolises bending of light around sharp edges like slits or boundaries of opaque objects etc.Due to this reason , we do not observe sharp boundary of shadow of an object. Instead around the boundary of shadow, we observe bands of bright and dark color which are also called fringes.
The phenomena of diffraction is explained by wave theory of light.
The ideal gas law allows a scientist to calculate the number of moles that the other gas laws do not. The ideal gas law is given as
P V = n RT
rearranging the equation by dividing both side by "RT", we get
PV/(RT) = nRT/(RT)
n = PV/(RT)
inserting the values of pressure, volume and temperature, we get number of moles.
To calculate the strength of the eye lens, we use the formula
( thin lens formula)
Here, u is the object distance and v is image distance.
Given, 
and 
Therefore,
Thus, strength of the eye lens is
Answer:
energy that behaves as if they were particles
Explanation:
Answer:
Explanation:
100 mph = 100 x 1760 x 3 / ( 60 x 60 )
= 146.67 ft / s
70 mph = 70 x 1760 x 3 / ( 60 x 60 )
= 102.67 ft/s
Let mass of the ball = m .
The ball which was moving with a velocity of 146.67 ft/s is turned back by the action of force of bat on the ball and it moved in opposite direction with velocity of - 102.67 ft/s ( - ve sign due to reversed direction )
If m be the mass of ball
change in momentum = m x 146.67 - ( - m x 102.67 )
= m x 146.67 + m x 102.67
= 249.34 m
Change in momentum = impulse = force x time
Putting the given values
249.34 m = force x 1 x 10⁻³ ( time = 10⁻³ s )
force = 249.34 m x 10³ poundal .
Here m is mass of the ball in lb .
