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stepan [7]
3 years ago
9

· A car moves at 12 m/s and coasts up a hill with a

Physics
1 answer:
Zigmanuir [339]3 years ago
7 0

Explanation:

Given that,

Initial speed of a car, u = 12 m/s

Aceleration, a = -1.6 m/s²

(a) The displacement of car after 6 seconds is :

d=ut+\dfrac{1}{2}at^2\\\\d=12\times 6+\dfrac{1}{2}\times (-1.6)\times 6^2\\\\d=43.2\ m

(b) The displacement of the car after 9 seconds is :

d=ut+\dfrac{1}{2}at^2\\\\d=12\times 9+\dfrac{1}{2}\times (-1.6)\times 9^2\\\\d=43.2\ m

Hence, this is the required solution.

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You stand 17.5 m from a wall holding a softball. You throw the softball at the wall at an angle of 30.5 ∘ from the ground with a
Levart [38]

Answer:

5.39 m

Explanation:

From kinematics

s=u_x t where t is time, s is distance and u_x is initial speed in x direction

u_x= 20.5cos 30.5=17.6634 m/s

u_y= 20.5 sin 30.5=10.40454 m/s

Now 17.5=17.6634 t

t=\frac {17.5}{17.6634} =0.99 s

Using the equation of kinematics

h=u_y t- 0.5gt^{2}

h=10.40454\times 0.99^{2}-0.5\times 9.81\times 0.99^{2}

h=5.39 m

5 0
3 years ago
Which statements describe acceleration? Check all that apply.
DiKsa [7]

Answer:

Negative acceleration occurs when an object speeds up in the negative direction.

Positive acceleration occurs when an object speeds up in the positive direction.

Explanation:

This might be wrong but I get some points for a answer..

8 0
3 years ago
Precipitation tends to be _______ on the _______ side of a mountain because water vapor _______ as it rises there.
Lera25 [3.4K]

Answer:

Higher, Windward side, Condenses

Explanation:

The Windward side refers to that side of a mountain that faces the direction from which the wind is blowing. In this direction, the moisture containing hot air blowing from a distant place moves upward and strikes the mountain at a greater height, where the air mass is thin and the temperature is relatively cold. As the temperature and pressure decrease with altitude, the hot uprising air cools and gradually condenses. This results in the occurrence of high precipitation over this region i.e. the windward side of the mountain.

Therefore, the precipitation is always higher on the windward side of a mountain as the hot air undergoes condensation at greater height as it rises upward.

6 0
3 years ago
A coil of wire with 50 turns lies in the plane of the page and has an initial area of 0.180 m2. The coil is now stretched to hav
butalik [34]

Answer:

Explanation:

Given that,

Number of turns of coil

N = 50 turns

Initial area of plane

A1 = 0.18 m²

The coil it stretch to a no area in time t = 0.1s

No area implies that the final area is 0, A2 = 0 m²

Constant magnetic field strength

B = 1.51 T

EMF?

EMF is given as

Using far away Lenz law

ε = —N• dΦ/dt

Where Φ = BA

Then,

ε = —N• d(BA)/dt

Since B is constant,

ε = —N•B dA/dt

ε = —N•B (∆A/∆t)

ε = —N•B(A2—A1)/(t2-t1)

ε = —50 × 1.51 (0—0.18)/(0.1—0)

ε =—75.5 × —0.18 / 0.1

ε = 135.9 V

The induced EMF is 135.9V

Fleming’s left hand rule stated that if the index finger points toward magnetic flux, the thumb towards the motion of the conductor, then the middle finger points towards the induced emf.

Since the area lines in the plane, then the induced emf will be out of the page

5 0
4 years ago
An automobile engine takes in 4000 j of heat and performs 1100 j of mechanical work in each cycle. (a) calculate the engine's ef
Semmy [17]
(a) The efficiency of an engine is defined as the ratio between the work done by the engine and the heat it takes in:
\eta= \frac{W}{Q_{in}}
The engine in this problem does a work of W=1100 J and it takes in Q_{in}=4000 J of heat, therefore its efficiency is
\eta= \frac{1100 J}{4000 J}=0.275 = 27.5 \%

(b) The heat taken by the machine is 4000 J; of this amount of heat, only 1100 J are converted into useful work. This means that the rest of the heat is wasted. Therefore, the wasted heat is the difference between the heat in input and the work done by the engine:
Q_{wasted}=Q_{in}-W=4000 J-1100 J=2900 J
7 0
3 years ago
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