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anzhelika [568]
3 years ago
5

Can I PLEASE get some help?

Physics
1 answer:
Rus_ich [418]3 years ago
3 0
1.) C
2.) B
3.) D
4.) B
Good luck with your work!
You might be interested in
A piece of steel is 11.5cm long at 22C. It is heated to 1221C, close to its melting point. How long is it, in cm, at the high te
Nataly [62]

Answer:

The length at the final temperature is 11.7 cm.

Explanation:

We need to use the thermal expansion equation:

\Delta L=\alpha L_{0}\Delta T

Where:

  • L(0) is the initial length
  • ΔT is the differential temperature, final temperature minus initial temperature (T(f)-T(0))
  • ΔL is the final length minus the initial length (L(f)-L(0))
  • α is the coefficient of linear expantion of steel (12.5*10⁻⁶ 1/°C)  

So, we have:

L_{f}-L_{0}=\alpha L_{0}(T_{f}-T_{0})

L_{f}=L_{0}+\alpha L_{0}(T_{f}-T_{0})

L_{f}=0.115+(12.5*10^{-6})(0.115)(1221-22)

L_{f}=0.117\: m

Therefore, the length at the final temperature is 11.7 cm.

I hope it helps you!

7 0
3 years ago
A golf ball is launched horizontally at a speed of 11 meters per second and a high of 6.4 m above the ground. How long will it t
Serjik [45]

The answer is A.

t = ( 2h / g )^1/2 = ( 2 x 6.4 / 9.8 )^1/2 = 1.14s

8 0
2 years ago
Three resistors of 15.0 ohms, 30.0 ohms, and 60.0 ohms respectively are connected in parallel to an applied potential difference
AVprozaik [17]
A).  The drawing looks like a ladder with 4 rungs.
One rung is a 90-volt battery.
The other 3 rungs are the 3 resistors.

b).  The equivalent resistance is the reciprocal of (1/15 + 1/30 + 1/60).
That's the reciprocal of  7/60, or about 8.571... ohms. 

c).  I = V/R = 90 / 8.571...  =  10.5 Amperes.

d).  The 60-ohm resistor is connected directly across the battery.

Power = V²/R = (90²) / 60  =  135 watts.  Better COOL that baby !
4 0
3 years ago
One thing that the federal government pays for with your tax dollars is
Lesechka [4]
Education is payed for with tax dollars
7 0
3 years ago
A friction-less pulley in the shape of a solid cylinder of mass 2.90 kg and radius 30.0 cm is used to draw water from a well. A
WINSTONCH [101]

Answer:

s=-38.332m

Explanation:

From the question we are told that

Cylinder of mass m=2.90 kg

Radius R=30.0 m

Mass of bucket M_b= 1.90 kg

Fall time T_f= 3.70 seconds

Generally the tension the bucket is mathematically given by

T-mg=ma

For cylinder

 T=I*\alpha

 where

I=1/2mR^2

a=R*\alpha

Giving

T=-1/2mR\alpha

Therefore

a=\frac{-mg}{m+1/2m}

a=\frac{-(1.9*9.81)}{1.9+0.5*(2.9)}

a=-5.563880597 \approx -5.6m/s^2

Generally the Newton's equation for motion is mathematically represented as

 s=ut+1/2at^2

 s=0(3)+1/2*-5.6*(3.7)^2

s=-38.332m

8 0
2 years ago
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