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IRINA_888 [86]
3 years ago
15

A jack for a car requires a force of 120 lbs to lift a 3,000 lb car. what is the ratio of the cars weight to the force required

to lift the car?
Physics
1 answer:
cestrela7 [59]3 years ago
7 0
A ratio can be written as a fraction and simplified.
120/3000
simplifies to 12/300
simplifies to 6/150
simplifies to 2/50
simplifies to 1/25 
so each 1 pound of force from the jack lifts 25 pounds of car.
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A storm is moving at 15 km/hr what to do to determine its velocity
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Check the current weather map for 2 different times, and see where the center of the storm is. That tells you what direction it's moving. With its speed and direction, you have its velocity.
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Explanation:

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Energy is converted from solar to chemical in Process A and then from one form of chemical to another in Process B. Process A is
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Read 2 more answers
A -turn rectangular coil with length and width is in a region with its axis initially aligned to a horizontally directed uniform
madam [21]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The maximum emf is \epsilon_{max}= 26.8 V

The emf induced at t = 1.00 s is \epsilon = 24.1V

The maximum rate of change of magnetic flux is   \frac{d \o}{dt}|_{max}  =26.8V

Explanation:

    From the question we are told that

        The number of turns is N = 44 turns

          The length of the coil is  l = 15.0 cm = \frac{15}{100} = 0.15m

          The width of the coil is  w = 8.50 cm =\frac{8.50}{100} =0.085 m

          The magnetic field is  B = 745 \ mT

          The angular speed is w = 64.0 rad/s

Generally the induced emf is mathematically represented as

        \epsilon = \epsilon_{max} sin (wt)

 Where \epsilon_{max} is the maximum induced emf and this is mathematically represented as

            \epsilon_{max} = N\ B\ A\ w

Where \o is the magnetic flux

            N is the number of turns

             A is the area of the coil which is mathematically evaluated as

             A = l *w

        Substituting values

           A = 0.15 * 0.085

               = 0.01275m^2

substituting values into the equation for  maximum induced emf

         \epsilon_{max} = 44* 745 *10^{-3} * 0.01275 * 64.0

                 \epsilon_{max}= 26.8 V

 given that the time t = 1.0sec

substituting values into the equation for induced emf  \epsilon = \epsilon_{max} sin (wt)

      \epsilon = 26.8 sin (64 * 1)

        \epsilon = 24.1V

   The maximum induced emf can also be represented mathematically as

              \epsilon_{max} = \frac{d \o}{dt}|_{max}

  Where  \o is the magnetic flux and \frac{d \o}{dt}|_{max} is the maximum rate at which magnetic flux changes the value of the maximum rate of change of magnetic flux is

         \frac{d \o}{dt}|_{max}  =26.8V

8 0
3 years ago
The frequency of the George Washington Bridge is 2.05 Hz. What is its period?
Zina [86]

Answer: 0.5 seconds

Explanation:

Given that:

Frequency of the George Washington Bridge F = 2.05 Hz

Period T = ?

Recall that frequency is the number of cycles a wave can complete in one second. Hence, frequency is the inverse of period.

i.e F = 1/T

2.05Hz = 1/T

T = 1/2.05Hz

T = 0.488 seconds (Rounded to the nearest tenth as 0.5seconds)

Thus, the period of the George Washington Bridge is 0.5 seconds

6 0
3 years ago
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