Answer:
Maximum altitude to see(L) = 1.47 × 10⁶ m (Approx)
Explanation:
Given:
wavelength (λ) = 0.12 nm = 0.12 × 10⁻⁹ m
Pupil Diameter (d) = 4.1 mm = 4 × 10⁻³ m
Separation distance (D) = 5.4 cm = 0.054 m
Find:
Maximum altitude to see(L)
Computation:
Resolving power = 1.22(λ / d)
D / L = 1.22(λ / d)
0.054 / L = 1.22 [(0.12 × 10⁻⁹) / (4 × 10⁻³ m)]
0.054 / L = 1.22 [0.03 × 10⁻⁶]
L = 0.054 / 1.22 [0.03 × 10⁻⁶]
L = 0.054 / [0.0366 × 10⁻⁶]
L = 1.47 × 10⁶
Maximum altitude to see(L) = 1.47 × 10⁶ m (Approx)
<h3><u>Answer;</u></h3>
B. 16.2 m/s
<h3><u>Explanation</u>;</h3>
Using the equation;
v = u + at; where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken;
u = 21 m/s, a= -2.4 m/s^2 and t = 2 seconds
Therefore;
v = 21 + ((-2.4) × 2)
= 21 - 4.8
<u> = 16.2 m/s</u>
B) 14.0 N
The way to solve this problem is to determine the kinetic energy the box had before and after the rough patch of floor. The equation for kinetic energy is:
E = 0.5 M V^2
where
E = Energy
M = Mass
V = velocity
Substituting the known values, let's calculate the before and after energy.
Before:
E = 0.5 M V^2
E = 0.5 13.5kg (2.25 m/s)^2
E = 6.75 kg 5.0625 m^2/s^2
E = 34.17188 kg*m^2/s^2 = 34.17188 joules
After:
E = 0.5 M V^2
E = 0.5 13.5kg (1.2 m/s)^2
E = 6.75 kg 1.44 m^2/s^2
E = 9.72 kg*m^2/s^2 = 9.72 Joules
So the box lost 34.17188 J - 9.72 J = 24.451875 J of energy over a distance of 1.75 meters. Let's calculate the loss per meter by dividing the loss by the distance.
24.451875 J / 1.75 m = 13.9725 J/m = 13.9725 N
Rounding to 1 decimal place gives 14.0 N which matches option "B".
We have to wonder what substance you're working with. Under normal, human environmental conditions, there are almost no substances that freeze and boil at the same temperature.
However, EVERY substance has SOME temperature, at some pressure, at which it "sublimes" ... passing directly from solid to gas, or from gas to solid, without existing in liquid form in between. Even water does that, if the conditions are right.
If you read the question carefully, you can find the answer right there in it.
In fact, you don't even have to read the whole question ... you only need to read one word.
In fact, you don't even have to read the whole word ... you only need to read part of the word.
The word to read is "wavelength".
The important part of the word is "length".
<em>Now</em> it's time to look at the picture:
#1 is a height.
#2 is a place on the wave
#4 is a place on the wave
<em>#3 </em>is the only thing in the picture that's a "length" of anything.
