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Komok [63]
3 years ago
13

The zeros of a polynomial are −1/2 and 3/7. Find the polynomial. ___x²+x− ___

Mathematics
2 answers:
faltersainse [42]3 years ago
7 0

Answer:

given zeroes are 1/2 &-3/7

let a=1/2 & b=-3/7

the formula of forming a quadratic equation when zeros are given is x²-(a+b)x+ab

a+b = 1/2+(-3/7)=7-6/14= 1/14

ab=1/2×(-3/7)=-3/14

=> equation is = x²-(1/14)x-3/14

<h2><u><em>hope it helps u!</em></u></h2><h2><u><em>Brainliest pls!!!</em></u></h2>
faltersainse [42]3 years ago
5 0

Answer:

y=14x^2+x-3

Step-by-step explanation:

If the zeros of the polynomial are -1/2 and 3/7 then:

\implies x=-\dfrac12

Add 1/2 to both sides:

\implies x+\dfrac12=0

Multiply both sides by 2:

\implies 2x+1=0

\implies x=\dfrac37

Subtract 3/7 from both sides:

\implies x-\dfrac37=0

Multiply both sides by 7:

\implies 7x-3=0

Therefore, the factored form of the polynomial is y=(2x+1)(7x-3)

Expanding the brackets so that the polynomial is in standard form:

\implies y=14x^2-6x+7x-3

\implies y=14x^2+x-3

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