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Nat2105 [25]
3 years ago
12

4 Math Questions 1.) a^2-10a=4 2.) x^2+20x-18=3 3.) (x-5)^2=1 4.) x^2-18x=65

Mathematics
2 answers:
natima [27]3 years ago
8 0

1) a=5+√29 or a=5−√29 2) x=1 or x=−21 3) x=4 or x=6 4) x=9+√146 or x=9−√146 Hopefully that helps you ❤

frez [133]3 years ago
4 0
1) a^2 -a^1 = 4/10
a = 2/5

2)x^2 + 20x = 3+18
x^2+x^1 =21/20
x=21/20

3)(x -5) (x-5) = 1
x^2- 5x -5x+25 = 1
x^2-10x = 1-25
x^2-10x= -24
x^2-x^1= -24/10
x=-12/5 (2/2/5)

4)x^2 -x^1 =65/18
x =3/11/18
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3 years ago
Kristen invests $ 5745 in a bank. The bank 6.5% interest compounded monthly. How long must she leave the money in the bank for i
podryga [215]

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2. 17.0 years

3. 2nd option

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A=P\cdot \left(1+\dfrac{r}{n}\right)^{nt},

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A is final value, P is initial value, r is interest rate (as decimal), n is number of periods and t is number of years.

In your case,

1. P=$5745, A=2P=$11490, n=12 (compounded monthly), r=0.065 (6.5%) and t is unknown. Then

11490=5745\cdot \left(1+\dfrac{0.065}{12}\right)^{12t},\\ \\2=(1.0054)^{12t},\\ \\12t=\log_{1.0054}2,\\ \\t=\dfrac{1}{12}\log_ {1.0054}2\approx 10.7\ years.

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12t=\log_{1.0054}3,

t=\dfrac{1}{12}\log_{1.0054}3\approx 17.0\ years.

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A=5745\cdot \left(1+\dfrac{0.0675}{4}\right)^{4\cdot 5},\\ \\A=5745\cdot (1.0169)^{20}\approx \$8032.58.

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