Answer:
Density = 11.4 g/cm³
Explanation:
Given data:
Density of lead = ?
Height of lead bar = 0.500 cm
Width of lead bar = 1.55 cm
Length of lead bar = 25.00 cm
Mass of lead bar = 220.9 g
Solution:
Density = mass/ volume
Volume of bar = length × width × height
Volume of bar = 25.00 cm × 1.55 cm × 0.500 cm
Volume of bar = 19.4 cm³
Density of bar:
Density = 220.9 g/ 19.4 cm³
Density = 11.4 g/cm³
No, it won't change the amount of reactants nor the products as a catalyst will only provide an alternative path where lower activation energy is needed for the process to take place.
hope this explains it
If it does, please give it a brainliest :)))
Answer:
85% of 20 is 17
Explanation:
You can multiply 85% and 20 or subtract 85% from 20.
Answer:
69% Ag, 10.5% S, 20.5% O.
Explanation:
Ag₂SO₄ → Molar mass = 311.8 g/mol
2 mol of Ag → 107.87g/m . 2m = 215.74 g
1 mol of S → 32.06g/m . 1m = 32.06 g
4 mol of O → 16g/m .4m = 64 g
Percentage composition will be:
(Mass of Ag/ Total mass) . 100
(215.74 g / 311.8 g) . 100 = 69 %
(Mass of S/ Total mass) . 100
(32.06 g / 311.8 g) .100 = 10.5%
(Mass of O/ Total mass) . 100
(64 g / 311.8 g) . 100 = 20.5 %
