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Amanda [17]
3 years ago
9

What does D represent?

Chemistry
2 answers:
Vitek1552 [10]3 years ago
5 0

Answer:

C. Reactants

I think soo

nadezda [96]3 years ago
4 0

Answer:

B. energy of reactants is the answer

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11) What is the volume of 4.92 grams of hydrogen gas at STP? (Show the work using dimensional analysis)
lorasvet [3.4K]

Answer:

The volume of 4.92 grams of hydrogen gas at STP is 9.105 litter.

Explanation:

We know that, the molecular weight of hydrogen gas (H_{2} ) = 1\times 2 = 2.

Moles of hydrogen gas = \frac{weight}{molecular weight}  = \frac{4.92}{2} = 2.46 moles.

At STP, 1 mole of hydrogen gas = occupies 22.4 litter

    So, 2.46 mole of hydrogen gas = occupies \frac{22.4}{2.46} = 9.105 litter.

Hence, the volume of 2.46 grams of hydrogen gas at STP is 9.105 litter.

4 0
2 years ago
Suppose that the root-mean-square velocity vrms of water molecules (molecular mass is equal to 18.0 g/mol) in a flame is found t
Zolol [24]

Answer:

T=954.41\ K

Explanation:

The expression for the root mean square speed is:

C_{rms}=\sqrt {\dfrac {3RT}{M}}

R is Gas constant having value = 8.314 J / K mol  

M is the molar mass of gas

Molar mass of water vapor = 18.0 g/mol  = 0.018 kg/mol

Temperature = ?

C_{rms}=1150  m/s

1150=\sqrt{\frac{3\times 8.314\times T}{0.018}}

1322500=\frac{24.942T}{0.018}

T=954.41\ K

4 0
3 years ago
What volume of 1.60 M hydrochloric acid solution (HCI) is required to neutralize 48.0 mL of 0.200 M sodium
nexus9112 [7]

Answer:

Volume of HCl require =  6 mL

Explanation:

Given data:

Volume of HCl require = ?

Molarity of HCl solution = 1.60 M

Volume of NaOH = 48.0 mL

Molarity of NaOH = 0.200 M

Solution:

Formula:

M₁V₁     =      M₂V₂

By putting values,

1.60 M×V₁  =  0.200 M×48.0 mL

V₁  =  0.200 M×48.0 mL/1.60 M

V₁  =  9.6 M .mL /1.60 M

V₁  =  6 mL

5 0
2 years ago
Which formula represents a hydrocarbon with a double covalent bond?
Nataliya [291]

Answer:

c is the answer

step by step explanation is not

4 0
2 years ago
Calorimeter containing 1000 grans of water the initial temperature of water is 24.85 degrees . the heat of water is 4.184 j/g de
kvasek [131]
<h3><u>Answer;</u></h3>

10.80 ° C

<h3><u>Explanation;</u></h3>

From the information given;

Initial temperature of water =  24.85°C

Final temperature of water = 35.65°C

Mass of water = 1000 g

The specific heat of water ,c = 4.184 J/g °C.

The heat capacity of the calorimeter  = 695 J/ °C

Change in temperature ΔT = 35.65°C - 24.85°C

                                             = 10.80°C

3 0
3 years ago
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