All categories

3 years ago

What does D represent?

Chemistry

2 answers:

Vitek1552 [10]3 years ago

5 0

Answer:

C. Reactants

I think soo

nadezda [96]3 years ago

4 0

Answer:

B. energy of reactants is the answer

You might be interested in

Five different substances are given to you to be dissolved in water. Which substances are most likely to undergo dissolution in

9966 [12]

Answer:

NaF and KBr

Explanation:

These two substances contain pure ionic bonds. LiI is a covalent compound because of the Large polarizing power of Li and the high polarizability of I(Fajan's rules). The other compounds mentioned are organic compounds. They are not soluble in water at all.

7 0

4 years ago

The scientific method is one application of critical thinking.true or false

kumpel [21]

The best answer between the two choices would be the first option TRUE because the scientific method is used to do more advance research and investigation on things.

3 0

4 years ago

Read 2 more answers

A) The average molecular speed in a sample of Ar gas at a certain temperature is 391 m/s. The average molecular speed in a sampl

diamong [38]

Answer:

For A: The average molecular speed of Ne gas is 553 m/s at the same temperature.

For B: The rate of effusion of $SO_2$ gas is $1.006\times 10^{-3}mol/hr$

Explanation:

For A:

The average molecular speed of the gas is calculated by using the formula:

$V_{gas}=\sqrt{\frac{8RT}{\pi M}}$

$V_{gas}\propto \sqrt{\frac{1}{M}}$

where, M is the molar mass of gas

Forming an equation for the two gases:

$\frac{V_{Ar}}{V_{Ne}}=\sqrt{\frac{M_{Ne}}{M_{Ar}}}$ .....(1)

Given values:

$V_{Ar}=391m/s\\M_{Ar}=40g/mol\\M_{Ne}=20g/mol$

Plugging values in equation 1:

$\frac{391m/s}{V_{Ne}}=\sqrt{\frac{20}{40}}\\\\V_{Ne}=391\times \sqrt{2}=553m/s$

Hence, the average molecular speed of Ne gas is 553 m/s at the same temperature.

For B:

Graham's law states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass of the gas. The equation for this follows:

$Rate\propto \frac{1}{\sqrt{M}}$

Where, M is the molar mass of the gas

Forming an equation for the two gases:

$\frac{Rate_{SO_2}}{Rate_{Xe}}=\sqrt{\frac{M_{Xe}}{M_{SO_2}}}$ .....(2)

Given values:

$Rate_{Xe}=7.03\times 10^{-4}mol/hr\\M_{Xe}=131g/mol\\M_{SO_2}=64g/mol$

Plugging values in equation 2:

$\frac{Rate_{SO_2}}{7.03\times 10^{-4}}=\sqrt{\frac{131}{64}}\\\\Rate_{SO_2}=7.03\times 10^{-4}\times \sqrt{\frac{131}{64}}\\\\Rate_{SO_2}=1.006\times 10^{-3}mol/hr$

Hence, the rate of effusion of $SO_2$ gas is $1.006\times 10^{-3}mol/hr$

8 0

3 years ago

PLZ HEL I WILL GIVE BRAINLIEST

NemiM [27]

Answer: A material that readily transmits energy is a conductor, while one that resists energy transfer is called an insulator .

i hope this will help u

pls add me as brainliest

8 0

3 years ago

Read 2 more answers

How many milliliters of a 0.900% (m/v) normal saline solution can be prepared from 3.50 g of sodium chloride, NaCl

Bess [88]

Answer:

389 mL solution

Explanation:

Step 1: Given data

Concentration of the NaCl solution: 0.900% (m/v)

Mass of sodium chloride: 3.50 g

Volume of saline solution: ?

Step 2: Calculate the volume of saline solution

The concentration of the NaCl solution is 0.900% (m/v), that is, there are 0.900 g of NaCl every 100 mL of solution.

3.50 g NaCl × 100 mL solution/0.900 g NaCl = 389 mL solution

5 0

3 years ago