Answer:
The rise in sea level it will be of 0.08 Km.
Explanation:
The relation between volume (V) and mass (m) is density (δ):
δ = m / V
First, knowing the volume of ice in the Antarctic and the density of the ice, it is possible to calculate the mass of ice that will melt:
m = δ.V =
The mass of ice is 2.77x1022 so, the mass of water entering the oceans is the same.
Second, knowing the mass of water and the density of water, it is possible to calculate the volume of water entering the oceans:
V = m / δ =
Third, assuming that the oceans of the world cover an area, A, of about 3.62 x 108 km2 and that the increase in volume of the oceans can be calculated as A x h:
h = V/A =
Hello!
We use the amount in grams (mass ratio) based on the composition of the elements, see: (in 100g solution)
C: 70.79% = 70,79 g
H: 8.91% = 8.91 g
N: 4.59% = 4.59 g
O: 15.72% = 15.72 g
Let us use the above mentioned data (in g) and values will be converted to amount of substance (number of moles) by dividing by molecular mass (g / mol) each of the values, lets see:
We note that the values found above are not integers, so let's divide these values by the smallest of them, so that the proportion is not changed, let's see:
T<span>hus, the minimum or empirical formula found for the compound will be:
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I hope this helps. =)
False
FM is typically limited to 30-40 miles while AM can go up to about 1000 miles
There are 4 quantum numbers that can be used to describe the space of highest probability an electron resides in.
First quantum number is the principal quantum number- n , states the energy level.
Second quantum number states the angular momentum quantum number - l,
states the subshell and the shape of the orbital
values of l for n energy shells are from 0 to n-1
third is magnetic quantum number - m, which tells the specific orbital.
fourth is spin quantum number - s - gives the spin of the electron in the orbital
here we are asked to find l for 3p1
n = 3
and values of l are 0,1 and 2
for p orbitals , l = 1
therefore second orbital for 3p¹ is 1.
Answer:
(a) 3-ethylpentane (because the longest chain is 5 carbon atoms, and ethyl is positioned at the 3rd carbon atom)
(b) 1, 2-dimethylbutane (because two methyl is positioned at the 2nd and 3rd carbon atom)
(c) 3, 4-dimethylhexane (the longest chain here is 6 carbon atoms, and two methyl is positioned at the 3rd and 4rd carbon atom)
(d) 3-methyl 4-ethylhexane ( the longest chain is 6 carbon atoms, one methyl is positioned at the 3rd carbon atom while one ethyl is positioned at the 4rd carbon atom)
(e) and (f) are similar to the question before... and I dunno how to (g) and (h) cuz I haven't learned it
Hope that you are able to answer the rest!!