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Andrews [41]
3 years ago
12

Determine if the data are qualitative or quantitative.

Chemistry
2 answers:
jonny [76]3 years ago
8 0
Hi there!
Zinc: Is qualitative
Chlorine: is quantitative
Gallium: is neither
Nitrogen: is quantitative
Aluminum: is quantitative
If you need an explanation, please let me know !
Hope this helps and have a good day :) !
~Angel
krek1111 [17]3 years ago
6 0

Answer:

Zinc: Is qualitative  

Chlorine: is quantitative  

Gallium: is qualitative  

Nitrogen: is quantitative  

Aluminum: is qualitative

Explanation:

EDGE2020

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Assume that the reaction of aqueous hydrobromic acid solution and potassium hydroxide base undergoes a complete neutralization r
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Answer:

a.

HBr + KOH → KBr + H  _{2} O

b.

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c.

0.042 M

d.

1.4

5 0
3 years ago
While estimating the Caloric content of the chemical constituents present in the food item, the carbohydrate amount is discounte
Mashcka [7]

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Fiber is "Not Digestible"

Explanation:

Carbohydrates that contain fiber cannot be completely digested. the indigestible components of fiber are measured in the calorimeter, but they are not accessible for energy in the human body.

5 0
3 years ago
Find the reagent to sythesize 1- phenyl-1-propanol
vova2212 [387]

Answer:

aqueous acid is used as a reagent.  

Explanation:

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in this reaction we also use the aqueous acid for the acidification as a reagent. We add aqueous acid when ethanol is present. This is because ethanol is get converted in the presence of aqueous acid into the chloroethane.  

4 0
3 years ago
Which of the following organisms is reproduced by regeneration?
scoundrel [369]
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4 0
3 years ago
Read 2 more answers
Two systems with heat capacities 19.9 J mol-1 K-1 and 28.2 ] mol 1 K-1 respectively interact thermally and come to an equilibriu
MAVERICK [17]

Answer : The initial temperature of system 2 is, 19.415^oC

Explanation :

In this problem we assumed that the total energy of the combined systems remains constant.

-q_1=q_2

m\times c_1\times (T_f-T_1)=-m\times c_2\times (T_f-T_2)

The mass remains same.

where,

C_1 = heat capacity of system 1 = 19.9 J/mole.K

C_2 = heat capacity of system 2 = 28.2 J/mole.K

T_f = final temperature of system = 30^oC=273+30=303K

T_1 = initial temperature of system 1 = 45^oC=273+45=318K

T_2 = initial temperature of system 2 = ?

Now put all the given values in the above formula, we get

-19.9J/mole.K\times (303-318)K=28.2J/mole.K\times (303-T_2)K

T_2=292.415K

T_2=292.415-273=19.415^oC

Therefore, the initial temperature of system 2 is, 19.415^oC

8 0
4 years ago
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