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Vilka [71]
2 years ago
15

The perimeter of the original rectangle is 16 feet. A small rectangle has a length of 6. 2 feet and width of 1. 8 feet. A larger

rectangle has a length of 12. 4 feet and width of blank. Not drawn to scale What is the perimeter of the enlarged rectangle? Round to the nearest tenth if necessary. 22. 3 feet 31 feet 32 feet 42. 7 feet.
Mathematics
1 answer:
ankoles [38]2 years ago
4 0

The perimeter of the enlarged rectangle is 32 ft and the width of the larger rectangle is 3.6 ft.

<h3>What is perimeter of plane?</h3>

The measure of the boundary of a plane or shape is called its perimeter. The perimeter of a plane or shape is the sum of all the sides.

A small rectangle has a length of 6.2 feet and width of 1.8 feet. The parameter of this triangle is,

P_s=6.2+1.8\\P_s=8\rm\; ft

The small rectangle has a length of 6.2 and the larger rectangle has a length of 12.4 feet. Thus the scale factor of enlargement is,

r=\dfrac{12.4}{6.2}\\r=2

The perimeter of the original rectangle is 16 feet and scale factor is 2. Thus, the perimeter of the enlarged rectangle is,

P_l=2\times16\\P_l=32\rm\; ft

The small rectangle has width of 1.8 feet and scale factor is 2. Thus, the width of the larger rectangle is,

w_l=1.8\times2\\w_1=3.6\rm\; ft

Hence, the perimeter of the enlarged rectangle is 32 ft and the width of the larger rectangle is 3.6 ft.

Learn more about the perimeter of plane here;

brainly.com/question/1662271

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Use the Polynomial Identity below to help you create a list of 10 Pythagorean Triples:
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Just choose 2 numbers from {1,2,3,4,5,6,7,8,...} and make sure the one you input for x is larger.

Post the three in the comments and I will check them for you.

Step-by-step explanation:

We need to choose 2 positive integers for x and y where x>y.

Positive integers are {1,2,3,4,5,6,7,.....}.

I'm going to start with (x,y)=(2,1).

x=2 and y=1.

(2^2+1^2)^2=(2^2-1^2)^2+(2\cdot2\cdot1)^2

(4+1)^2=(4-1)^2+(4)^2

(5)^2=(3)^2+(4)^2

So one Pythagorean Triple is (3,4,5).

I'm going to choose (x,y)=(3,1).

x=3 and y=1.

(3^2+1^2)^2=(3^2-1^2)^2+(2\cdot3\cdot1)^2

(9+1)^2=(9-1)^2+(6)^2

(10)^2=(8)^2+(6)^2

So another Pythagorean Triple is (6,8,10).

I'm going to choose (x,y)=(3,2).

x=3 and y=2.

(3^2+2^2)^2=(3^2-2^2)^2+(2\cdot3\cdot2)^2

(9+4)^2=(9-4)^2+(12)^2

(13)^2=(5)^2+(12)^2

So another is (5,12,13).

I'm going to choose (x,y)=(4,1).

(4^2+1^2)^2=(4^2-1^2)^2+(2\cdot4\cdot1)^2

(16+1)^2=(16-1)^2+(8)^2

(17)^2=(15)^2+(8)^2

Another is (8,15,17).

I'm going to choose (x,y)=(4,2).

(4^2+2^2)^2=(4^2-2^2)^2+(2\cdot4\cdot2)^2

(16+4)^2=(16-4)^2+(16)^2

(20)^2=(12)^2+(16)^2

We have another which is (12,16,20).

I'm going to choose (x,y)=(4,3).

(4^2+3^2)^2=(4^2-3^2)^2+(2\cdot4\cdot3)^2

(16+9)^2=(16-9)^2+(24)^2

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We have another is (7,24,25).

You are just choosing numbers from the positive integer set {1,2,3,4,... } and making sure the number you plug in for x is higher than the number for y.

I will do one more.

Let's choose (x,y)=(5,1).

(5^2+1^2)^2=(5^2-1^2)^2+(2\cdot5\cdot1)^2

(25+1)^2=(25-1)^2+(10)^2

(26)^2=(24)^2+(10)^2

So (10,24,26) is another.

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(5^2+2^2)^2=(5^2-2^2)^2+(2\cdot5\cdot2)^2

(25+4)^2=(25-4)^2+(20)^2

(29)^2=(21)^2+(20)^2

So another Pythagorean Triple is (20,21,29).

Choose (x,y)=(5,3).

(5^2+3^2)^2=(5^2-3^2)^2+(2\cdot5\cdot3)^2

(25+9)^2=(25-9)^2+(30)^2

(34)^2=(16)^2+(30)^2

Another Pythagorean Triple is (16,30,34).

Let (x,y)=(5,4)

(5^2+4^2)^2=(5^2-4^2)^2+(2\cdot5\cdot4)^2

(25+16)^2=(25-16)^2+(40)^2

(41)^2=(9)^2+(40)^2

Another is (9,40,41).

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3 years ago
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Andreas93 [3]
I'm not sure for number one, but for number 2 the answer to that one is the second tallest on the chart or on the histogram. For number 3 I'm not sure because i cant see the numbers there too blurry. I'm sorry but i hope i got the second one correct.
3 0
3 years ago
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