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Genrish500 [490]
3 years ago
11

I don’t really know how to do this and need help

Chemistry
2 answers:
zhannawk [14.2K]3 years ago
8 0

\\ \sf\Rrightarrow 3545530

\\ \sf\Rrightarrow 354553

\\ \sf\Rrightarrow 35455

\\ \sf\Rrightarrow 3545

\\ \sf\Rrightarrow 355

schepotkina [342]3 years ago
6 0

Answer:

Explanation:

To round the number to 3 significant figures, look at the first 4 digits: 3545 which will round to 355. The number in 3 significant figures will be 3,550,000.

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A trial of this decomposition experiment, using different quantities of reactants than those listed in the question above produc
Paul [167]

Answer : The volume of O_2(g) produced at standard conditions of temperature and pressure is 0.2422 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of O_2 gas = (740-22.4) torr = 717.6 torr

P_2 = final pressure of O_2 gas at STP= 760 torr

V_1 = initial volume of O_2 gas = 280 mL

V_2 = final volume of O_2 gas at STP = ?

T_1 = initial temperature of O_2 gas = 25^oC=273+25=298K

T_2 = final temperature of O_2 gas = 0^oC=273+0=273K

Now put all the given values in the above equation, we get:

\frac{717.6torr\times 280mL}{298K}=\frac{760torr\times V_2}{273K}

V_2=242.2mL=0.2422L

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5 0
3 years ago
32 gm of O2 to mole of O2
lana [24]

Molar mass of O2:-

\\ \rm\longmapsto 2(16u)=32g/mol

Now

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\\ \rm\longmapsto No\:of\;moles=1mol

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A gas is initially at a pressure of 4.7 atm and a volume of 7.5 L. When the volume is increased to 10.5 L, what is the new press
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Answer:

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It is a chemical reaction


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