The sampling distribution is illustrated below.
<h3>How to illustrate the sampling?</h3>
Based on the information given, the population is illustrated as 1, 4, 7. The sample without replacement will be:
<u>Sample Mean</u>
1 and 4. 2.5
1 and 7. 4
4 and 7. 5.5
The population mean will be:
= (1 + 4 + 7)/3
= 4
The sample mean is an unbiased estimator of the population mean.
The sampling with replacement illustrates that the mean will be:
= 36/9 = 4
Also, when n = 3, the number of samples will be:
= 3³ = 27
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Answer:
DB = CA (Proved)
Step-by-step explanation:
Statement 1.
∠D = ∠C, M is the midpoint of DC and ∠1 = ∠2
Reason 1.
Given
Statement 2.
Between Δ DBM and Δ CAM,
(i) DM = CM,
(ii) ∠D = ∠C and
(iii) ∠DMB = ∠CMA
Reason 2.
(i) given
(ii) given and
(iii) ∠ DMB = ∠1 + ∠AMB and ∠CMA = ∠2 + ∠AMB
Since ∠1 = ∠2, so, ∠DMB = ∠CMA.
Statement 3.
Δ DBM ≅ Δ CAM
Reason 3.
By angle-side-angle rule.
Statement 4.
DB = CA
Reason 4.
Corresponding sides of two congruent triangles. (Answer)
Answer:
3645 rabbits after 6 months.
Step-by-step explanation:
The population of a rabbit colony triples each month.
This means that the population of the colony after t months is given by:
In which P(0) is the initial population.
The population started with 5 rabbits.
This means that 
So
How many rabbits are there after 6 months?
This is P(6). So
3645 rabbits after 6 months.
Let's find the least possibilities:
First number: 6
Second number: 8
Third number: 10
6 + 8 + 10 = 24
Now we can see that we are still missing 31 - 24 = 7.
7 can be gained by adding 3 and 4, so:
First number: 6 + 3 = 9
Second number: 8 + 4 = 12
Third number: 10
9 + 12 + 10 = 31
<span>We add all these numbers up.
137.50 +162.50+92.50= 392.50$
Use a cacl or by hand</span>
