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3 years ago

Which force is represented by the arrow at A?

Physics

1 answer:

Tanzania [10]3 years ago

3 0

Answer:Gravity is a force of attraction that exists between any two masses, any two bodies, any two particles. Gravity is not just the attraction between objects and the Earth. It is an attraction that exists between all objects, everywhere in the universe.Friction is the resistance to motion of one object moving relative to another. It is not a fundamental force, like gravity or electromagnetism. Instead, scientists believe it is the result of the electromagnetic attraction between charged particles in two touching surfaces.

The normal force is the force that surfaces exert to prevent solid objects from passing through each other. Normal force is a contact force. If two surfaces are not in contact, they can't exert a normal force on each other.The tension force is defined as the force that is transmitted through a rope, string or wire when pulled by forces acting from opposite sides. The tension force is directed over the length of the wire and pulls energy equally on the bodies at the ends.

Explanation:

You might be interested in

What determines the strength of a base?

Anvisha [2.4K]

The higher the dissociation constant the stronger the acid or base. Since electrolytes are created as ions are freed into solution there is a relationship between the strength of an acid, a base, and the electrolyte it produces. Acids and bases are measured using the pH scale.

5 0

3 years ago

Read 2 more answers

A pendulum consists of a 1.5 kg stone swinging on a 4.3 m string of negligible mass. The stone has a speed of 8.4 m/s when it pa

Ad libitum [116K]

Answer:

(a) v = 1.54m/s, (b) Θ = 80.6° and (c) E = 52.92J

Explanation:

(a) At the lowest point, the total energy is giving by:

$E_{T}_{0} = E_{K}_{0} + E_{P}_{0} = \frac {1}{2} mv_{0}^{2} + mgy_{0}$

where, $E_{K}$ : kinetic energy, $E_{P}$ : potential energy, m: pendulum's mass, v: speed of the pendulum, g:gravity and y: heigh of the pendulum.

$E_{T}_{0} = \frac {1}{2} mv_{0}^{2} + mg(0) = \frac {1}{2} (1.5)(8.4)^{2} = 52.92 J$ (1)

When the string is at 64° from the vertical, the total energy is:

$E_{T}_{f} = \frac {1}{2} mv_{f}^{2} + mgy_{f}$ (2)

At this point, $y_{f}$ is:

$y_{f} = L - Lcos(\Theta)$ (3)

where L: longitude of the pendulum

$y_{f} = 4.3 m (1 -cos(64)) = 2.42 m$

By conservation of energy, we can calculate the speed of the string, at 64 ° to the vertical. Equaling equations (1) and (2):

$E_{T}_{0} = E_{T}_{f} = \frac {1}{2} mv_{f}^{2} + mgy_{f}$

$v_{f} = \sqrt \frac{2(E_{T}_{0} - mgy_{f})}{mg}}$

$v_{f} = \sqrt \frac{2(52.92 - 1.5 \cdot 9.8 \cdot 2.42)}{1.5 \cdot 9.8}} = 1.54 \frac{m}{s}$

(b) Smilarly, by conservation of energy we can find the greatest angle, assuming that vf = 0 at the greatest angle reached:

$\frac {1}{2} mv_{0}^{2} + mgy_{0} = \frac {1}{2} mv_{f}^{2} + mgy_{f}$

$y_{f} = \frac {E_{0}}{mg} = \frac {52.92}{(1.5)(9.8)} = 3.6 m$

Using the heigh calculated in equation (3) we can find the angle:

$\Theta = Arccos (\frac {L - y_{f}}{L}) = Arccos (\frac {4.3 - 3.6}{4.3}) = 80.6^\circ$

(c) The total mechanical energy at the lowest point is giving by:

$E_{T} = E_{K} + E_{P} = \frac {1}{2} mv_{0}^{2} + 0 = \frac {1}{2} (1.5)(8.4)^{2} = 52.92 J$

Have a nice day!

8 0

3 years ago

Is it true that theodor Schwann used only his own research to develop the cell theory?

slamgirl [31]

No, there were other scientists who developed the cell theory with him.

8 0

4 years ago

Two bicyclists ride towards each other along a long straight road, each with a constant speed of 10 km/h. When they are 20 km ap

maw [93]

Answer:

Explanation:

A )

As the two bicycles come closer , the time period of oscillation of bee to oscillate between the two is gradually reduced . It is akin to a pendulum with gradually decreasing amplitude . It will be infinite number of trips the bee will travel before it gets squished .

B )

The bee will survive until the two bicyclists meet each other .

time of their meeting = distance between them / their relative velocity

= 20 / ( 10 + 10 )

= 1 hour .

C )

Total distance travelled by bee during 1 hour

= time x speed of bee

= 1 x 30 km/h

= 30 km .

8 0

3 years ago

Two teams of nine members each engage in a tug of war. Each of the first team’s members has an average mass of 65 kg and exerts

Leviafan [203]

Answer:

.team 1 a = 20.8 m/s² team 2 a = 19.2 m/s²

Explanation:

Let's use Newton's second law to calculate the acceleration of the two groups

F = ma

a = F / M

Group 1

a = 9 1354/9 65

a = 20.8 m / s²

Group 2

a = 9 1364/9 71

a = 19.2 m / s²

If the two groups pull against each other, group 1 should win, by creating a greater acceleration.

Δa = 20.8 -19.2

Δa = 1.6 m / s²

4 0

4 years ago