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oksano4ka [1.4K]
3 years ago
15

When temperature decreases but actual water vapor content remains the same, what happens to relative humidity?

Physics
2 answers:
ruslelena [56]3 years ago
8 0

Answer:

d. Relative humidity increases.

Explanation:

The expression of relative humidity in terms of absolute humidity, absolute pressure and saturation pression at measured temperature is:

\phi = \frac{\omega \cdot P}{(0.622+\omega)\cdot P_{sat}}

When temperature decreases, the saturation pressure decreases also and, consequently, relative humidity increases. Therefore, the right answer is option D.

vaieri [72.5K]3 years ago
3 0

Answer:

d. Relative humidity increases

Explanation:

Relative humidity is defined as the amount of water vapor which can be found in air.

When temperature decreases and the actual water vapor content remains the same the relative humidity increases.

When the temperature increases and the actual water vapor content remains the same the relative humidity decreases.

This is because air at a higher temperature needs more moisture for it to get saturated than air with a lower temperature.

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You are trying to find out how high you have to pitch a water balloon in order for it to burst when it hits the ground. You disc
FrozenT [24]

Answer:

The balloon hit the ground with velocity -15.34 m/s

Explanation:

<em>Lets explain how to solve the problem</em>

You found that the best height to pitch a water balloon in order for it to

burst when it hits the ground is 12 meters.

We consider that the 12 meters is the maximum height, so the velocity

at this height is zero.

To find the velocity when the balloon hits the ground lets use the rule

<em>v² = u² + 2gh</em>, where v is the final velocity, u is the initial velocity, g is

the acceleration of gravity and h is the height.

u = 0 , h = 12 m , g = 9.8 m/s²

<em>Substitute these values in the equation above</em>

v² = 0 + 2(9.8)(12)

v² = 235.2

<em>Take square root for both sides</em>

v = ± \sqrt{235.2}

The velocity is downward, then it's a negative value

Then v = -15.34 m/s

<em>The balloon hit the ground with velocity -15.34 m/s</em>

6 0
3 years ago
3. A dog walks a distance of 100 ft. in 20 s of time. What is the dog's
natta225 [31]
The answer is A.
100/20=5
8 0
3 years ago
Read 2 more answers
Which statement is true of cooling down after physical activity? A cool-down is a period of semistrenuous activity after physica
Xelga [282]
The statement that is true of cooling down after physical activity is that you should cool down for about 5 to 10 minutes after being physically active.
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3 years ago
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In a charging process, 4 × 1013 electrons are removed from one small metal sphere and placed on a second identical sphere. Initi
Alina [70]

Answer:

The distance between the two spheres is 914.41 X 10³ m

Explanation:

Given;

4 X 10¹³ electrons, and its equivalent in coulomb's is calculated as follows;

1 e = 1.602 X 10⁻¹⁹ C

4 X 10¹³ e = 4 X 10¹³ X 1.602 X 10⁻¹⁹ C = 6.408 X 10⁻⁶ C

V = Ed

where;

V is the electrical potential energy between two spheres, J

E is the electric field potential between the two spheres N/C

d is the distance between two charged bodies, m

V = \frac{K*q}{d^2}*d = \frac{K*q}{d}

d = \frac{K*q}{V}

where;

K is coulomb's constant = 8.99 X 10⁹ Nm²/C²

d = (8.99 X 10⁹ X 6.408 X 10⁻⁶)/0.063

d = 914.41 X 10³ m

Therefore, the distance between the two spheres is 914.41 X 10³ m

3 0
3 years ago
An air-track glider attached to a spring oscillates between the 10.0 cm mark and the 57.0 cm mark on the track. The glider compl
pickupchik [31]

Answer:

a. 2.1 s

b.0.48 Hz

c. A=24cm

d. 72cm/s

Explanation:

An air-track glider attached to a spring oscillates between the 10.0 cm mark and the 57.0 cm mark on the track. The glider completes 15.0 oscillations in 31.0 s.What are the (a) period, (b) frequency, (c) amplitude, and (d) maximum speed of the glider?

What are the  period,

period is the time taken for a wave particle to make one complete oscillation

a) 31 / 15 = 2.066 seconds

= 2.1 s

(b) frequency : this the number of oscillation made in one seconds.

it is also the inverse of the period.

= oscillations / time

= 15/31= 0.48 Hz

(c) amplitude : maximum displacement from the origin

amplitude = 1/2 of the difference of oscillation marks

= 1/2(57-10) = 47/2cm

23.5cm

A=24cm

(d) maximum speed of the glider?

V=ωA

angular frequency *Amplitude

V=a*pi*f*amplitude

2π x frequency x amplitude = maximum speed

= 2π x .48 x 24

=72.38 cm/s

72cm/s

5 0
3 years ago
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