The time it will take if a car change the velocity from 36m/s to 28m/s with an acceleration of -2.0m/s² is 4s.
<h3>How to calculate deceleration?</h3>
Deceleration is the amount by which a speed or velocity decreases (and so a scalar quantity or a vector quantity).
The deceleration of a body can be calculated using the following formula:
-a = (v - u)/t
Where;
- -a = deceleration
- v = final velocity
- u = initial velocity
- t = time in seconds
-2 = (28 - 36)/t
-2t = -8
t = 4s
Therefore, the time it will take if a car change the velocity from 36m/s to 28m/s with an acceleration of -2.0m/s² is 4s.
Learn more about deceleration at: brainly.com/question/4403243
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Answer: C) The kinetic energy and the entropy of the water molecules increases through fusion.
Explanation:
(a) The stone travels a vertical distance <em>y</em> of
<em>y</em> = (12.0 m/s) <em>t</em> + 1/2 <em>g t</em> ²
where <em>g</em> = 9.80 m/s² is the acceleration due to gravity. Note that this equation assume the downward direction to be positive, and that <em>y</em> = 0 corresponds to the height from which the stone is thrown.
So if it reaches the ground in <em>t</em> = 1.54 s, then the height of the building <em>y</em> is
<em>y</em> = (12.0 m/s) (1.54 s) + 1/2 (9.80 m/s²) (1.54 s)² ≈ 30.1 m
(b) The stone's (downward) velocity <em>v</em> at time <em>t </em>is
<em>v</em> = 12.0 m/s + <em>g t</em>
so that after <em>t</em> = 1.54 s, its velocity is
<em>v</em> = 12.0 m/s + (9.80 m/s²) (1.54 s) ≈ 27.1 m/s
(and of course, speed is the magnitude of velocity)
Answer:
Explanation:
The formula for time period of a pendulum is given as follows :
T = 2π
l is length of pendulum and g is acceleration due to gravity .
So time period of pendulum is not dependent on the mass of the pendulum . If time period is same and length is also the same then acceleration due to gravity will also be the same . Hence the acceleration due to gravity at distant planet will be same as that on the earth.