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nadya68 [22]
3 years ago
15

A free positive charge released in an electric field will _____

Physics
1 answer:
morpeh [17]3 years ago
4 0

Answer:

Accelerates in the same direction as the field

Explanation:

When a charge is immersed in an electric field, the charge experiences an electric force, whose magnitude is given by

F = qE

where q is the magnitude of the charge and E is the magnitude of the electric field.

The direction of the force depends on the sign of the charge. In particular,

- For a positive charge, F and E have the same direction

- For a negative charge, F and E have opposite directions

Therefore, a free positive charge will experience a force in the same direction as the field - therefore, it will accelerate in the same direction.

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What is the wavelength of a wave that has a speed of 26 m/s and a frequency of 49? ? Show your work
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3 years ago
Hi, so i have to find T1, can some1 help?
iragen [17]

30.1 N

Explanation:

Given:

W_1 = 16\:\text{N}

W_2 = 8\:\text{N}

Let's write the components of the net forces at the intersections. Note that the system is equilibrium so all the net forces are zero.

<u>Forces</u><u> </u><u>involving</u><u> </u><u>W1</u><u>:</u>

x:\:\:\:-T_1 + T_3\cos \alpha = 0\:\: \\ \text{or}\:\:T_2 = T_3\cos \alpha\:\:\:\:\:(1)

y:\:\:\:T_3\sin \alpha - W_1 = 0\:\:\: \\ \text{or}\:\:\:T_3\sin \alpha = W_1\:\:\:\:\:\:(2)

<u>Forces</u><u> </u><u>involving</u><u> </u><u>W2</u><u>:</u>

x:\:\:\:T_1\sin 53 - T_3\sin \alpha = W_2\:\:\:\:\:\:\:(3)

y:\:\:\:T_4 - T_1\cos 53 - T_3\cos \alpha = 0\:\:\:\;(4)

Substitute (2) into (3) and we get

T_1\sin 53 - W_1 = W_2

Solving for T_1,

T_1 = \dfrac{W_1 + W_2}{\sin 53} = 30.1\:\text{N}

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3 years ago
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