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3 years ago

A free positive charge released in an electric field will _____

Physics

1 answer:

morpeh [17]3 years ago

4 0

Answer:

Accelerates in the same direction as the field

Explanation:

When a charge is immersed in an electric field, the charge experiences an electric force, whose magnitude is given by

F = qE

where q is the magnitude of the charge and E is the magnitude of the electric field.

The direction of the force depends on the sign of the charge. In particular,

- For a positive charge, F and E have the same direction

- For a negative charge, F and E have opposite directions

Therefore, a free positive charge will experience a force in the same direction as the field - therefore, it will accelerate in the same direction.

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a girl pushes a cart to the left a 100-N force. a boy pushes it to the right with a 50-N force. The net force exerted on the car

AURORKA [14]

Since the net force is the amount of force favoring the side with the most force acted upon it,

100 - 50 = 50

50N to the left

Hope this helps!

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4 years ago

A mountain climber of mass 60.0 kg slips and falls a distance of 4.00 m, at which time he reaches the end of his elastic safety

Sever21 [200]

The energy that the rope absorbs from the climber is Ep=m*g*h where m is mass of the climber, g=9.81m/s² and h is the height the climber fell. h=4 m+2 m because he was falling for 4 meters and the rope stretched for 2 aditional meters. The potential energy stored in the rope is Er=(1/2)*k*x², where k is the spring constant of the rope and x is the distance the rope stretched and it is
x=2 m. So the equation from the law of conservation of energy is:

Ep=Er

m*g*h=(1/2)*k*x²

k=(2*m*g*h)/x² = (2*60*9.81*6)/2² = 7063.2/4 =1765.8 N/m

So the spring constant of the rope is k=1765.8 N/m.

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3 years ago

One of two 25-year-old identical twins begins a trip on a spaceship traveling at 0.8 c while her twin remains on Earth. The twin

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3 years ago

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sladkih [1.3K]

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3 years ago

Read 2 more answers

At time t=0 a grinding wheel has an angular velocity of 30.0 rad/s . It has a constant angular acceleration of 35.0 rad/s2 until

Rama09 [41]

Answer:

(A) 570 rad

(B) 10 s

Explanation:

The equations of motion for circular motions are used.

Initial angular velocity, $\omega_0 = 30.0 \text{ rad/s}$

Angular acceleration, $\alpha =35.0 \text{ rad/s}^2$

(A)

At t = 2.00 s, the angular displacement, θ, is given by

$\theta = \omega_0t+\frac{1}{2}\alpha t^2 = (30\times 2) + \frac{1}{2}\times35\times2^2=60+70 = 130\text{ rad}$

After this time, it decelerates through an angular displacement of 440 rad.

Total angular displacement = 130 + 440 rad = 570 rad

(B)

At the time the circuit breaker tips, the angular velocity is given by

$\omega = \omega_0+\alpha t = 30.0+(35.0\times 2) = 30.0+70.0 =100.0\ \text{rad/s}$

This becomes the initial angular velocity for the decelerating motion. Because it stops, the final angular velocity is 0 rad/s. The time for this part of the motion is calculated thus:

$\theta_2 = \left(\dfrac{\omega_i+\omega_f}{2}\right)t$