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Dafna11 [192]
3 years ago
10

Which of the following best describes the difference between a mixture and a pure substance? A. A mixture is made up of only one

type of atom; a pure substance is made up of more than one type of atom. B. A mixture is made up of more than one type of atom; a pure substance is made up of only one type of atom. C. A mixture has the same properties throughout; a pure substance has the different properties throughout. D. A mixture has different properties throughout; a pure substance has the same properties throughout.
Chemistry
1 answer:
katrin2010 [14]3 years ago
8 0

Answer:

D. A mixture has different properties throughout; a pure substance has the same properties throughout.

Explanation:

hope this helps :(

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Which of these scenarios contains an exact number?
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The scenario that contains an exact number is 'A) You count 10 people in a room' (Option A).

<h3>What is the exact number?</h3>

An exact number can be considered a discrete variable because it does not involve a continuous range of values in a given measurement.

In conclusion, the scenario that contains an exact number is 'A) You count 10 people in a room' (Option A).

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4 0
2 years ago
Aluminum reacts with hydrochloric acid to produce aluminum chloride and hydrogen gas. 2 al(s) + 6 hcl(aq) → 2 alcl3(aq) + 3 h2(g
MariettaO [177]
Aluminum reacts with hydrochloric acid to produce aluminum chloride and hydrogen gas. 2 al(s) + 6 hcl(aq) → 2 alcl3(aq) + 3 h2(g) what mass of h2(g) is produced from the reaction of 1.35 g al(s) with excess hydrochloric acid?
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4 years ago
n the formation of chloromethane and hydrogen chloride. The overall reaction is 2CH4(g)+3Cl2(g)⟶2CH3Cl(g)+2HCl(g)+2Cl−(g) 2CH4(g
IrinaVladis [17]

Answer:

The total pressure in the flask is 0,619 atm.

Explanation:

For the reaction:

2CH₄(g) + 3Cl₂(g) ⟶ 2 CH₃Cl(g) + 2HCl(g) + 2Cl⁻(g)

The moles of CH₄ in 295 mL at STP are:

n = PV/RT

Where P is pressure (1 atm), V is volume (0,295L), R is gas constant (0,082atmL/molK) and T is temperature (273,15 K)

Replacing, moles of CH₄ are <em>0,0132 moles</em>

In the same way, moles of chlorine are <em>0,0324 moles</em>

As 3 moles of Cl₂ react with 2 moles of CH₄, for a total reaction of 0,0132 moles of CH₄ you need:

0,0132 moles CH₄ × \frac{3 moles Cl_{2}}{2 moles CH_{4}} = <em>0,0198 moles Cl₂. </em>That means that 0,0324-0,0198 = <em>0,0126 moles of Cl₂ are in excess.</em>

As the reaction reaches in 77%, the moles of CH₄ that don't react are:

0,0132×(100%-77%)= <em>3,036x10⁻³ moles of CH₄</em>

Also, the moles of Cl₂ that don't react are:

0,0126 + 0,0198×(100%-77%)= <em>0,0172 moles of Cl₂</em>

The moles produced of each compound are:

0,0132×77% × \frac{2 moles CH_{3}Cl}{2 moles CH_{4}} = <em>0,0102 moles of CH₃Cl -</em><em>that are the same moles of HCl and Cl⁻</em><em>-</em>

Thus, total moles in the flask are:

<em>3,036x10⁻³ moles of CH₄ + 0,0172 moles of Cl₂ + 0,0102 moles of CH₃Cl + 0,0102 moles of HCl + 0,0102 moles of  Cl⁻ = </em><em>0,0507 total moles</em>

As the volume of the flask is 2,00L and the final temperature is 298 K. The total pressure in the flask is:

P = nRT/V

<em>P = 0,619 atm</em>

<em> </em>

I hope it helps!

3 0
4 years ago
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