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trapecia [35]
3 years ago
15

What is the mass, in grams, of 0.0490 mol of iron(III) phosphate

Chemistry
1 answer:
horrorfan [7]3 years ago
7 0

Answer:

m = 7.39 g.

Explanation:

Hello!

In this case, since the molar mass of iron (III) phosphate is 150.82 g/mol based on its molecular formula (FePO₄), we can compute the mass in grams of 0.0490 moles of this compound by setting up the following dimensional analysis:

m=0.0490mol*\frac{150.82g}{1mol} \\\\m=7.39 g

Best regards!

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I NEED HELP PLEASE, THANKS!
ira [324]

Answer:

About 0.652

Explanation:

Because the reaction is balanced, we can go straight to the next step. The molar mass of potassium is about 39.098, while the molar mass of hydrogen gas is 2 and the molar mass of water is 18. Therefore, 25.5g of potassium would be about 0.652 moles, and 220 grams of water would be about 12.222 moles, making potassium the limiting reactant. Since there is a single unit of each compound on both sides of the equation, there would be an equal amount of moles of potassium and hydrogen, and therefore about 0.652 moles of hydrogen gas would be produced. Hope this helps!

6 0
3 years ago
If the volume of a gas at 0.5 atm changes from 150 mL to 75 mL, what is the new pressure?
prisoha [69]

Answer:

<h2>1 atm</h2>

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we're finding the new pressure

P_2 =  \frac{P_1V_1}{V_2}  \\

We have

P_2 =  \frac{0.5 \times 150}{75}  =  \frac{75}{75}  = 1 \\

We have the final answer as

<h3>1 atm</h3>

Hope this helps you

5 0
3 years ago
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xxMikexx [17]

Answer:

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Explanation:

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For example, 3.02 → 3 significant figures

When you have 0 on the left in the measure, we do not consider as a sgnificant figures

For example 0.0010 → 2 significant figures (10)

3.0 → 2 significant figures (0 is on the right, not the left)

7 0
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D.
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This is balanced.
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3 years ago
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Vinvika [58]
B the girls arm will act as a pulley
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