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trapecia [35]
3 years ago
15

What is the mass, in grams, of 0.0490 mol of iron(III) phosphate

Chemistry
1 answer:
horrorfan [7]3 years ago
7 0

Answer:

m = 7.39 g.

Explanation:

Hello!

In this case, since the molar mass of iron (III) phosphate is 150.82 g/mol based on its molecular formula (FePO₄), we can compute the mass in grams of 0.0490 moles of this compound by setting up the following dimensional analysis:

m=0.0490mol*\frac{150.82g}{1mol} \\\\m=7.39 g

Best regards!

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