The temperature change if 400 J of energy is added to 10 grams of water is 9.57°C.
<h3>How to calculate temperature change?</h3>
The temperature change of a calorimeter can be calculated using the following expression:
E = mc∆T
Where;
- E = energy in joules
- m = mass
- c = specific heat capacity = 4.18J/g°C
- ∆T = change in temperature
400 = 10 × 4.18 × ∆T
400 = 41.8∆T
∆T = 400/41.8
∆T = 9.57°C
Therefore, the temperature change if 400 J of energy is added to 10 grams of water is 9.57°C.
Learn more about change in temperature at: brainly.com/question/11464844
(a) In this section, give your answers to three decimal places.
(i)
Calculate the mass of carbon present in 0.352 g of CO
2
.
Use this value to calculate the amount, in moles, of carbon atoms present in 0.240 g
of
A
.
(ii)
Calculate the mass of hydrogen present in 0.144 g of H
2
O.
Use this value to calculate the amount, in moles, of hydrogen atoms present in 0.240 g
of
A
.
(iii)
Use your answers to calculate the mass of oxygen present in 0.240 g of
A
Use this value to calculate the amount, in moles, of oxygen atoms present in 0.240 g
of
A
(b)
Use your answers to
(a)
to calculate the empirical formula of
A
thank you
hope it helpsss
Answer:
2-ethly-3-5 dimethylheptam
Explanation:
trust meeeeee
Answer:
3. doubles
Explanation:
for an ideal gas behavior, the relationship between volume and temperature is given by Charles law
Charles law states that the volume of a given mass of gas is directly proportional to its temperature provided that pressure remains constant. Mathematically, this is represented as
V ∝ T
V=KT
K = V/T
where V is the volume of the gas
T is the Temperature
k represents the constant of proportionality
For initial and final conditions of a gas,
= 
where 1 and 2 represent initial and final conditions respectively
therefore, T₁ = 100 and T₂ = 200
= 
200 × V₁ = 100 × V₂
divide both sides by 100
2V₁ = V₂
final volume,V₂ = 2V₁
there the volume doubles
I legitimately think it's 87.3 grams
