PLEASE HELP!!! I HAVE CLASS IN LIKE 10 MIN!!!

What is the unit rate of 2.99 for 14 pounds

natali 33 [55]

It is .21 or 21 cents for each pound.

8 0

4 years ago

Help find the missing lengths round to nearest tenth

Mama L [17]

Answer:

Step-by-step explanation:

Theta is 21 degrees

x is the adjacent side
8 is the opposite side
y is the hypothenuse

SOH - CAH - TOA

Since the opposite side is given and we need to find the length of the adjacent side, we can use tangent to solve for x.

$tan 21=\frac{opposite}{adjacent} \\tan 21 =\frac{8}{x} \\0.384 =\frac{8}{x} \\0.384x =8 \\x=\frac{8}{0.384} \\x=20.84$

Since the opposite side is given and we need to find the length of the hypotenuse, we can use sine to solve for y.

$sin 21=\frac{opposite}{hypotenuse} \\sin21 =\frac{8}{y} \\0.358 =\frac{8}{y} \\0.358y=8 \\y=\frac{8}{0.358} \\y=22.32$

6 0

3 years ago

Graphing Form for Linear Equations in 2 variables.

NeX [460]

X-intercept: y = 0
y-intercept: x = 0

3x + 4y = 0

x-intercept: subtitute y = 0
3x + 4 · 0 = 0
3x = 0
x = 0 → (0; 0)

y-intercept: subtitute x = 0
3 · 0 + 4y = 0
4y = 0
y = 0 → (0; 0)

3 0

3 years ago

Circle the tens digit in each number 31, 94, 17

Georgia [21]

3 in 31, 9 in 96, 1 in 17.

3 0

3 years ago

Read 2 more answers

survey on televisions requiring repairs within four years was conducted. Nineteen out of 200 televisions from company A and 25 o

Fudgin [204]

Answer:

$z=\frac{0.095-0.125}{\sqrt{0.11(1-0.11)(\frac{1}{200}+\frac{1}{200})}}=-0.959$

$p_v =P(Z$

Comparing the p value with the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to to FAIL to reject the null hypothesis, and we can't conclude that company A are more reliable than televisions from company B at 5% of significance.

Step-by-step explanation:

Data given and notation

$X_{1}=19$ represent the number of tvs who need a repair for A

$X_{2}=25$ represent the number of tvs who need a repair for B

$n_{1}=200$ sample 1 selected

$n_{2}=200$ sample 2 selected

$p_{1}=\frac{19}{200}=0.095$ represent the proportion estimated for the sample A

$p_{2}=\frac{25}{200}=0.125$ represent the proportion estimated for the sample B

$\hat p$ represent the pooled estimate of p

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

$\alpha=0.05$ significance level given

Concepts and formulas to use

We need to conduct a hypothesis in order to check if company A are more reliable than televisions from company B (that means p1<p2) , the system of hypothesis would be:

Null hypothesis: $p_{1} \geq p_{2}$

Alternative hypothesis: $p_{1} < p_{2}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{19+25}{200+200}=0.11$

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.095-0.125}{\sqrt{0.11(1-0.11)(\frac{1}{200}+\frac{1}{200})}}=-0.959$

Statistical decision

Since is a left sided test the p value would be:

$p_v =P(Z$

Comparing the p value with the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to to FAIL to reject the null hypothesis, and we can't conclude that company A are more reliable than televisions from company B at 5% of significance.

4 0

3 years ago