Explanation:
desk I have a lot of work and I will send it in the one
Answer:nothing beats the chemistry between us :) smooth right?
Explanation:I’m pretty sure u have to show the part before the questions so that people can respond to it since there is no info on how to answer the question :p
Answer:
7.506 g
Explanation:
In order to answer the first question we need to keep in mind the requested concentration of acetate: 0.250 M. With the concentration and the volume we can calculate the required moles and then the required grams:
0.250 M * 0.500 L = 0.125 moles acetate
0.125 moles * 60.05 g/mol = 7.506 g
So 7.506 g of acetic acid will be needed to prepare the buffer.